how to extract minor version from major version variable

[Sameer Modak]

Hello Team,

What is the correct way to extract just major version from full version like ,

full version is : 2.8.3

need version: 2.8

do we use split or regex 

[Sameer Modak]

 i tried with  regex_replace('^([0-9])\\.([0-9]*).*', '\\1.\\2')

but is there any other better way to do it

[Todd Lewis]

If you can manage to express your problem in terms of a test, then you can use Ansible's version test: https://docs.ansible.com/ansible/latest/collections/ansible/builtin/version_test.html

Otherwise, Ansible's own utils/version.py (which is used by the version test) uses the following regex. Maybe that will inspire you.

# Regular expression taken from
# https://semver.org/#is-there-a-suggested-regular-expression-regex-to-check-a-semver-string
SEMVER_RE = re.compile(
    r'''
    ^
        (?P<major>0|[1-9]\d*)
        \.
        (?P<minor>0|[1-9]\d*)
        \.
        (?P<patch>0|[1-9]\d*)
        (?:
            -
            (?P<prerelease>
                (?:0|[1-9]\d*|\d*[a-zA-Z-][0-9a-zA-Z-]*)
                (?:\.(?:0|[1-9]\d*|\d*[a-zA-Z-][0-9a-zA-Z-]*))*
            )
        )?
        (?:
            \+
            (?P<buildmetadata>[0-9a-zA-Z-]+(?:\.[0-9a-zA-Z-]+)*)
        )?
    $
    ''',
    flags=re.X
)

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-- 
Todd