Accessing hashes of lists

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James Morgan

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Nov 4, 2014, 11:55:20 AM11/4/14
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Hi,

I need to store information about applications in a variable data structure and access it via key.

If I store the information as follows I can access using with_items


- hosts: localhost
  connection: local
  vars:
    apps:
      admin:
        - service: admin
          handler: /admin
          port: 1200
          ....
      rpt:
        - service: rpt
          handler: /rpt
          port: 1234
          ....
  tasks:
    - debug:
        msg: "{{ item.service }} = {{ item.port }}"
      with_items: apps.admin

TASK: [debug ] **************************************************************** 
ok: [localhost] => (item={'handler': '/admin', 'port': 1200, 'service': 'admin'}) => {
    "item": {
        "handler": "/admin", 
        "port": 1200, 
        "service": "admin"
    }, 
    "msg": "admin = 1200"
}

How can I access one of the nested variables directly keying on application. The following won't work.

    - debug:
        msg: "{{ apps.admin.service }}"

TASK: [debug ] **************************************************************** 
fatal: [localhost] => One or more undefined variables: 'list' object has no attribute 'service'

I can't use with_items as I need to call lots of roles. I don't want to pass the information directly to the roles as variables as I want to have it defined in one place and it needs to be used in multiple places.

I.e application configuration and apache virtual host definitions.

Any help most appreciated.

I'm happy to change the structure. All I need to do is store an amount of information keyed by application

Thanks

James


Matt Martz

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Nov 4, 2014, 11:59:45 AM11/4/14
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In your example, `apps.admin` actually contains a list of dictionaries.  So accessing it would be: `apps.admin[0].service`.

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Matt Martz
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James Morgan

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Nov 4, 2014, 12:11:48 PM11/4/14
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Thanks, I think I need to reconsider my data structure.

I need to be able to iterate over applications in a group in some situations  but also key in by application name in others

I'll have a think.

Thanks
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