Remove items from a variable with reject

[Kernel Panic]

Hello

I want to remove items from a variable using reject filter, I have something like this:

vars:

    myvar:

      - item1

      - item2

List is the output of a command which contains  contains item1, item2 , item3, item4, item5, I want to remove item1 and 2 ( from myvar ) from the list with the code below

but is not working, any idea what am I doing wrong of different way to accomplish this?

  - set_fact:

        list_of_items: "{{ list.stdout_lines | reject('search', item ) | list  }}"

      with_items: "{{ myvar }}"

Thanks

Regards

[Vladimir Botka]

On Sun, 17 May 2020 13:57:57 -0700 (PDT)
Kernel Panic <netwar...@gmail.com> wrote:

> List ... contains contains item1, item2, item3, item4, item5. I want to

> remove item1 and 2 (from myvar)
>

> - set_fact:
> list_of_items: "{{ list.stdout_lines|
> reject('search', item )|
> list }}"
> with_items: "{{ myvar }}"

Use filter "difference". For example

- set_fact:
list_of_items: "{{ list.stdout_lines|difference(my_var) }}"

HTH,
-vlado

[Kernel Panic]

That did the trick.!!!! 

Thank you so much!!!