How to convert a dictionary to a list with key=value elements or to a string with key=value elements?

[Dmitriy Panteleyev]

Given an arbitrary dictionary like:

test:
  one: wan
  two: too
  three: tree

How can I convert it to a list like:

test:
  - one=wan
  - two=too
  - thee=tree

The end result that I need is actually a string of these list items ("one=one, two=too, three=tree").  I know that I can easily `join()` a list of items, but if there is an easier way to directly convert the dictionary to a string, that would work too.

Again, I know neither the number of dictionary elements, nor the key names.

A solution that works in version 2.5 would be best...

[Matt Martz]

This should do the trick:

{{ test|dictsort|map('join', '=')|join(', ') }}

In my test, it produces:

ok: [localhost] => {

    "msg": "one=wan, three=tree, two=too"

}

It's ordered slightly different than your version, and dictsort could help change the sort order, however just a note that python dictionaries in most python versions are unsorted.

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Matt Martz
@sivel
sivel.net

[Dmitriy Panteleyev]

I'll give that a try, thank you.

[Dmitriy Panteleyev]

Is there a way to modify this so that the item to the right of the equal sign was quoted?

So...  one="wan", two="too", three="tree"

[Kai Stian Olstad]

On Saturday, 20 October 2018 17:59:07 CEST Dmitriy Panteleyev wrote:
> Is there a way to modify this so that the item to the right of the equal
> sign was quoted?
>
> So... one="wan", two="too", three="tree"

You can always use Jinja template

- debug: msg="{% for k, v in test.iteritems() %}{{ k }}="{{ v }}"{% if not loop.last %}, {% endif %}{% endfor %}"

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Kai Stian Olstad

[Dmitriy Panteleyev]

That is what I ended up doing, but was curious if there is a 'filter' way.