Users - passwords - not getting it
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Brian Dunbar
May 28, 2014, 12:32:58 PM5/28/14
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I want to create an account, and a password. Then tell the user what that password is.
I have the same problem when I use this
shell: mkpasswd --method=SHA-512
The thing I'm not getting - and I'm sure this is a mental block, or a mis-understanding in something very basic - is 'where is the password'?
I've got a crypted value, but I don't know how to translate
"stdout": "$6$JQtu3Wqyrv..KM$3MtcEkDzm5OJ2.3jWUb3Oy.opnu1NmxPJ72vX2Q7skAOggdwa0sto/wlinld7QaAqbcVUdxo6Fo/UtqekVt6L/"}
to
"logmein"
~brian
Adam Heath
May 28, 2014, 1:21:37 PM5/28/14
to ansible...@googlegroups.com
On 05/28/2014 11:32 AM, Brian Dunbar wrote:
> mkpasswd --method=SHA-512
>
That runs mkpasswd with stdin unattached. If you run it manually,
you'll see it prompting for a password. If you run it multiple times,
and keep hitting enter(simulating a disconnected stdin), then you'll get
different values each time. This is due to a random salt being used($6
is the type of hashing, then the second $$ is the salt).
> mkpasswd --method=SHA-512
>
That runs mkpasswd with stdin unattached. If you run it manually,
you'll see it prompting for a password. If you run it multiple times,
and keep hitting enter(simulating a disconnected stdin), then you'll get
different values each time. This is due to a random salt being used($6
is the type of hashing, then the second $$ is the salt).
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