Hi,
If I have 2 application shortcuts A and B on home screen :
1. Press A -> starts app A
2. Press Home button
3. Press B -> starts app A (and not B)
So I first need to exit app A before launching app B. I understand the behavior (because DS is an unique instance from Android's point of view), but is there a better view to manage this small issue (for exemple by calling app.Exit() from OnPause event in each applications) ?
Pascal G.