Gabriel Obregon-Henao
unread,Aug 20, 2019, 1:13:26 PM8/20/19Sign in to reply to author
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Thanks Mike,
I had watched your lecture before and the way I’m doing it, as of now, is that I temporally-downsample the Morlet Wavelet decomposition such that there’s a 50% overlap between windows at my highest frequency (200 Hz). I’m using Fieldtrip and I compute the effective length of the temporal windows, at each frequency, as tw = cfg.gwidth * (cfg.width ./ pi * cfg.foi). I’m not sure if this is the non-empirical way of computing the FWHM that you vouch for in your 2018 paper, and that’s something else I’ll have to look into as I’m currently defining my wavelets based on number of cycles. For the effective width of the spectral window, at each frequency, I use fw = 2 * cfg.foi ./ cfg.width, and in theory I could choose the center frequencies such that there’s a given percent of overlap between the spectral windows. As of now, I choose an arbitrary number of wavelets to cover my entire frequency range (2 - 200 Hz), and that was the point I was trying to bring up with “downsampling” in the frequency dimension (i.e., is there an optimal way of choosing the number of wavelets, and if so, is it based on percentage of overlap?). If I define the center frequencies in logspace, I get multiple frequencies in the lower frequency ranges (e.g., if I use 90 wavelets to tile the entire frequency range, I get 8 frequencies between 2 and 3 Hz), and I think this might be affecting the sensitivity of my statistical tests. I’ve been thinking on splitting my analyses in 2, and computing the spectral decomposition via wavelets or the STFT for frequencies between 2 - 30 Hz, and using multitaper for frequencies between 30 - 200 Hz. Could you please remind me how the center frequencies are defined by default for the STFT and the Multitaper method? Is it based on the number of samples of the entire signal?
Thanks,
-Gabriel