Hi,subject to populationdensity {i in 1..m,j in 1..n,t in 1..T}: N[i,j,t] = NB[i,j,t] *(1-(W[i,j]* x[i,j,t])) + ((GR/VR) * SeedBank[i,j,t]);
The population density(N[i,j,t]) changes for each period(t). For 3 period problem below is the result shown.I expect the results to be shown as N[*,*,1] , N[*,*,2], N[*,*,3], but the result i got is different. Can you suggest to get the results in the correct format.How to get the result in non-transpose '(tr)' .RESULT :--N [1,*,*] (tr): 1 2 3 :=0 2 2 21 85.72 85.72 85.722 3748.69 3748.69 3748.693 167650 167650 163937[2,*,*] (tr): 1 2 3 :=0 2 2 21 85.72 85.72 85.722 3748.69 3748.69 3748.693 167053 163937 167650[3,*,*] (tr): 1 2 3 :=0 2 2 21 85.72 85.72 85.722 3748.69 3748.69 3748.693 163938 163937 167650;
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If you specify "display N" then AMPL will choose which index to "slice" through; in general it will be an index that gives the most compact display, but if there is more than one possibility for giving the most compact display then AMPL will make a choice arbitrarily. In the tables that result, if there are more columns than rows then AMPL will automatically transpose them, as indicated by "(tr)" at the beginning of each table.
To force a slice through the third index, you can write
display {t in 0..T}: {i in 1..m, j in 1..n} N[i,j,t];
To discourage transposing, change the option display_transpose from its default of 0 to a sufficiently large negative value; say, "option display_transpose -10;". For a more detailed explanation see chapter 12 of the AMPL book, www.ampl.com/BOOK/download.html.
Bob Fourer
From: am...@googlegroups.com [mailto:am...@googlegroups.com]
On Behalf Of Rajesh Kumar Narasimhan
Sent: Friday, November 09, 2012 8:16 PM
To: am...@googlegroups.com
Subject: [AMPL 6303] Three Dimensional Array