Re: [AMPL 24007] ampl.eval

[AMPL Google Group]

Is k a variable in Python or an AMPL parameter? If it is a variable in python you should use the following instead:

ampl.eval('display _varname, _var > "/home/monpc/optimal_sizing/ampl_results/solution{}.out";'.format(k))

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Filipe Brandão
am...@googlegroups.com

{#HS:1940369161-110838#}

On Tue, Jul 5, 2022 at 4:08 PM UTC, AMPL Modeling Language <am...@googlegroups.com> wrote:

In python script, I have a loop, each loop I solve an ampl optimization problem. I want to store all variables for each optimization as follows: (k is the number of the current loop)

ampl.eval('display _varname, _var > ("/home/monpc/optimal_sizing/ampl_results/solution" & k & ".out");')

However I got this error:

File "/home/monpc/optimal_sizing/main.py", line 593, in <module>
ampl.eval('display _varname, _var > ("/home/monpc/optimal_sizing/ampl_results/solution" & k & ".out");')

File "/home/monpc/anaconda3/lib/python3.9/site-packages/amplpy/ampl.py", line 263, in eval
self._error_handler_wrapper.check()

File "/home/monpc/anaconda3/lib/python3.9/site-packages/amplpy/ampl.py", line 697, in check
raise exp

File "/home/monpc/anaconda3/lib/python3.9/site-packages/amplpy/ampl.py", line 681, in error
self.error_handler.error(exception)

File "/home/monpc/anaconda3/lib/python3.9/site-packages/amplpy/errorhandler.py", line 25, in error
raise exception

AMPLException: line 1 offset 0
syntax error

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