Consulting solve_result_num using AMPL C++ API for baron

[C_Zetina]

Hello,

I am currently using teh AMPL C++ API to solve a problem in Baron. I would like to know if there is a way to extract the solve_result_num from within my code and assign it to a variable in my own code. 

I need this information to distinguish what instances Baron has solved to optimality andwhen it has timed out. Below is the code in C++ which forms a small part of the larger code I am implementing.  

*******

extern "C" double AMPL_solve(char *instance, char *temp, double obval) {

  double retval;

  try{

  ampl::AMPL ampl;

  ampl.setOption("solver", "baron");

  ampl.setOption("baron_options","optfile BaronOpt.txt outlev 1");

  ampl.setOption("omit_zero_rows","1");

  

  // Read the model and data files.

  std::string modelDirectory = "./PONDP";

  std::string dataDirectory = "./PONDP/NetDesign/";

  ampl.read(modelDirectory + "/PO_UNDP.mod");

  ampl.readData(dataDirectory + instance);

  ampl.readData(dataDirectory + "GE");

  //Adjusting the value of the gravit_exp

  // Solve

  ampl.solve();

          I ASSUME I WOULD QUERY FOR SOLVE_RESULT_NUM HERE.

  // Get objective entity by AMPL name

  ampl::Objective profit = ampl.getObjective("Profit");

  // Print it

  std::cout << instance << " objective function is: " << profit.value() << std::endl;

  // Get the values of the variable in a dataframe object

  ampl::Variable x = ampl.getVariable("x");

  ampl::DataFrame df = x.getValues();

  

  retval=profit.value()-obval;

  // Print them

  ofstream myfile;

  myfile.open (temp);

  myfile << df.toString();

  myfile.close();

  std::cout << df.toString() << std::endl;

  return retval;

  }

  catch (const std::exception &e)

  {

    std::cout << e.what() << "\n";

return -1;

  }

  

}

******

Thank you in advance for your time.

Regards

Carlos

[AMPL Google Group]

Dear Carlos,

You can access solve_result_num with ampl.getValue("solve_result_num").dbl() as follows:
int solve_result_num = (int)ampl.getValue("solve_result_num").dbl();

Best regards,
Filipe

--
Filipe Brandão
am...@googlegroups.com

{#HS:646486887-20501#}

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