That's a right triangle you idiot
M. S. Cramer
"the square of any given side is equal to the sum of the square of the
remainding sides". This can't be true unless all of the sides are 0 so what
did he mean to say?
T.D.C.
VoVat
He was attempting to quote the Pythagorean Theorem, which states that, in a
right triangle, the square of the hypotenuse is equal to the sum of the squares
of the other two sides. Homer's misquote was "The sum of the square roots of
any two sides of an isosceles triangle is equal to the square root of the
remaining side." The exact same misquote was made by the Scarecrow in "The
Wizard of Oz" (the movie, not the book).
Nathan Mulac DeHoff
Temporarily on AOL, but you can also reach me at:
Dinne...@tmbg.org
http://www.geocities.com/Area51/Corridor/5447/
"I'm a lonely, insignificant speck on a has-been planet orbited by a cold,
indifferent sun!" --Homer Jay Simpson
CoryanderX
>"the square of any given side is equal to the sum of the square of the
>remainding sides". This can't be true unless all of the sides are 0 so what
>did he mean to say?
I think it's that the square of the hypotenuse is equal to the sums of the
squares of the other two sides.
Sunshine
It's not peace I want, not mere
contentment. It's boundless joy
and ecstasy for me.
-Kugell
The world is full of magical
things, patiently waiting for
our wits to grow sharper.
-Eden Phillpotts
Rock me, Dr. Zaius!
MagmaGirl
>"the square of any given side is equal to the sum of the square of the
>remainding sides". This can't be true unless all of the sides are 0 so what
>did he mean to say?
He's Homer. Did you expect him to know what he was talking about?
Mag
"If you think back, and replay your year, if it doesn't bring you tears of
either joy or sadness, consider the year wasted." -- John Cage, "Ally McBeal"
"Problem is just a bleak word for challenge." -- Richard Fish, "Ally McBeal"
The WAV King
to put it to rest. Just go ahead and push me.
BTW it's a RIGHT triangle you idiot
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MagmaGirl wrote in message <19990109013039...@ng28.aol.com>...
Joey Joe-Joe Jr. AKA Gary
--
Your bestest pal,
Joey Joe Joe Jr. AKA Gary
Visit my web page @ www.come.to\spyland
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The WAV King wrote in message <7780cf$hil$1...@ash.prod.itd.earthlink.net>...
Fester
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Joey Joe-Joe Jr. AKA Gary <garo...@hotmail.com> wrote in message
news:bILl2.13615$Hy5....@news.rdc1.md.home.com...
MagmaGirl
>to put it to rest. Just go ahead and push me.
No no anything but that! :)
T.M
The joke is from the Wizard of Oz in which the Scarecrow makes the same
error as Homer does. I forget how the pythagorem theorm works....c'mon you
math nerds help me out...
M. S. Cramer <scr...@vt.edu> wrote in article
<776q5s$e1s$1...@solaris.cc.vt.edu>...
> When Homer put on Henry Kissinger's glasses he says something like
> "the square of any given side is equal to the sum of the square of the
> remainding sides". This can't be true unless all of the sides are 0 so
what
> did he mean to say?
>
> T.D.C.
>
>
Darrel Jones
T.M wrote in message <01be3be6$64eca5e0$255c65cc@default>...
>
>The joke is from the Wizard of Oz in which the Scarecrow makes the same
>error as Homer does. I forget how the pythagorem theorm works....c'mon you
>math nerds help me out...
>
the sum of squares of the lengths of the other two sides". Put another way,
if the hypotenuese (long side) of a right triangle is of length z and the
other sides are of length x and length y, then (x^2)+(y^2)=(z^2). This
theorem may be famous because it's so provable; 370 different proofs have
been published in one book, including one by an American President.
MagmaGirl
Sides of a Right Triangle are A, B and C.
A + B = C
right?
Rich Bunnell
>
> Pythagorean Theorem (as I remember...a lot of math was pushed out of my brain):
>
> Sides of a Right Triangle are A, B and C.
> A + B = C
>
> right?
Nope. It's A squared + B squared = C squared.
--
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-
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----------------------------------------------
Darrel Jones
MagmaGirl wrote in message <19990110005445...@ng112.aol.com>...
>>Close...
>>A² + B² = C².
>
>Er, I mean square-rooted them. See what I mean about math being pushed out
of
>my brain?
>
No. Try A=3, B=4, and C=5. Then A squared plus B squared is equal to C
squared, but A plus B is not equal to C.
Jon Blum
A² + B² = C².
Ugh, I'm getting rusty... I had to check Character map for the superscript
Alt-combo...
-Jon Blum
MagmaGirl <magm...@aol.com> wrote in message
news:19990109174452...@ng-fa1.aol.com...
>Pythagorean Theorem (as I remember...a lot of math was pushed out of my
brain):
>
>Sides of a Right Triangle are A, B and C.
>A + B = C
>
>right?
>
MagmaGirl
>A² + B² = C².
So if you cubed those squares...wouldn't it still be A + B = C?
MagmaGirl
>A² + B² = C².
Er, I mean square-rooted them. See what I mean about math being pushed out of
my brain?
Mag (downloaded a new Simpsons desktop theme. Everytime I post a note Grampa
yells "Ahh! Kill it! Killll iiiit!")
David Puckett
Darrel Jones wrote in message <779k8m$m79$1...@ultra.sonic.net>...
>>>A² + B² = C².
>>
>>Er, I mean square-rooted them. See what I mean about math being pushed
out
>of
>>my brain?
>>
>squared, but A plus B is not equal to C.
Or, simply put, the square root of the sum of two sqares don't equal the sum
of the square root of a square and the square root of another square (okay,
maybe NOT simply put...)
Any other math teachers read this NG?
Andrew Gill
<36987...@wznews.webzone.net>...
>
> Or, simply put, the square root of the sum of two sqares don't equal
the sum
> of the square root of a square and the square root of another square
(okay,
> maybe NOT simply put...)
Or, to put it another way,
(a + b)^2 = a^2 +2ab +b^2.
versus
a^2 + b^2 = c^2
The quantity 2ab is the difference between the two, and so they are NOT
the same. Taking the square root of the first will give you (a + b),
but the second will give you nothing useful.
> Any other math teachers read this NG?
No. I'm a math student.
--
|Andrew A. Gill |I posted to Silent-Tristero and|
|<fruadman_tru...@juno.com> |all I got was this stupid sig! |
|alt.tv.simpsons CBG-FAQ author | |
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Maybe I oughta learn TeX...
The WAV King
>A² + B² = C².
>
>Alt-combo...
How do you do it?How do you do it?How do you do it?How do you do it?How do
you do it?How do you do it?How do you do it?How do you do it?How do you do
it?How do you do it?How do you do it?How do you do it?How do you do it?How
do you do it?How do you do it?How do you do it?How do you do it?How do you
do it?How do you do it?How do you do it?How do you do it?How do you do
it?How do you do it?How do you do it?How do you do it?How do you do it?How
do you do it?How do you do it?How do you do it?How do you do it?How do you
do it?How do you do it?How do you do it?How do you do it?How do you do
it?How do you do it?How do you do it?How do you do it?How do you do it?
I'm lazy too!!!!!!!! But I want to know
The WAV King
routine
MagmaGirl
for bringing up grammar! :) That's what I get for dropping out of
pre-calculus in high school and deciding to forget everything mathematic I
learned past multiplication and division...
I can prove that 1+1 doesn't always equal 2. What about two drops of water?
Mag
Darrel Jones
David Puckett wrote in message <36987...@wznews.webzone.net>...
>
>Darrel Jones wrote in message <779k8m$m79$1...@ultra.sonic.net>...
>>
>>MagmaGirl wrote in message
<19990110005445...@ng112.aol.com>...
>>>>Close...
>>>
>out
>>of
>>>my brain?
>>>
>>No. Try A=3, B=4, and C=5. Then A squared plus B squared is equal to C
>>squared, but A plus B is not equal to C.
>
>
sum
>of the square root of a square and the square root of another square (okay,
>maybe NOT simply put...)
>
>
>
I'm not actually a math teacher, but I played one in math class... :)
Jon Blum
Scrape a mildly useful chunk of math goodness out of my brain, or use
Character map?
For the former, try to stay awake in class, for the latter, open up
Character map, note the Alt - xxxx combination in the lower right corner,
and hold the alt key while punching in the numbers. (Oh, and make sure
Numlock's on, too.)
Fun for the whole family! =)
-Jon Blum
>>A² + B² = C².
>>
>>Ugh, I'm getting rusty... I had to check Character map for the superscript
>>Alt-combo...
>
>How do you do it?
<Snipped the excessive use of copy/paste>
MagmaGirl
>Scrape a mildly useful chunk of math goodness out of my brain
MMM...free goo...
el...@imap3.asu.edu
know I expect ALL my Presidents to be astounding mathemeticians; anything
proven by a President must be correct... Not that I doubt the theorum...