~ I'd Like to Know ~
What, exactly, is the difference between a pound mass (lbm), and a
pound force (lbf)? Does anybody know?
Donald Shead <u10...@snet.net>
In a 1 g gravitational field, or on a space ship in
outer space accelerating at 1 g, not much, except that mass
refers to the resistance to acceleration of a defined
quantity of matter.
If you want me to go into the units of pounds,
poundals, Newtons, etc., sorry, I don't want to.
I am content to consider 1 pound of force to
be that which will accelerate 1 pound mass at 1 g.
There is a problem with this in advanced physics,
but I never do anything advanced. :-)
Ken Fischer
You first have to be clear about the difference between mass and
force. There are various levels at which these can be defined.
At high-school level you might say that force is something which
acts on a body's mass, while mass is the quantity of matter on
which the force acts. Mass is a scalar, force is a vector.
The key is Newton's equation:
Force = mass * acceleration.
You can then set about defining units. This is usually (but not
necessarily) done by thinking of a mass suspended or falling under
gravity. Suppose we talk in SI units, since these make a clearer
distinction between mass and force. The SI unit of mass is the
kilogram and gravitational acceleration g is almost 10 m/s**2.
So a mass of 1 kg experiences a gravitational force of 1 kg *
10 m/s**2 = 10 units. This force is commonly called the weight
of the body. The SI force unit is called a Newton.
Things become more complicated in the old Imperial units. Suppose
we suspend or drop a 1 lb mass in a gravitational field. The
acceleration is about 32 ft/s**2. The weight of the body is then
1 lb(m)* 32 ft/s**2 = 32 units of force. The unit of force here
is called a poundal.
Alternatively we can choose to measure force in lb, as lbf. The
mass unit then has to be force/acceleration. This mass unit is
called a slug (really!).
Just to mess things up fully, you could choose to measure mass in
lbm and force in lbf but that's equivalent to using an acceleration
of 1 ft/s**2 in Newton's equation or normalising the gravitational
units with respect to g.
Regards,
Dr Ron Thomson
Ballistics + Impact Group
Glasgow University