Google Groups no longer supports new Usenet posts or subscriptions. Historical content remains viewable.
Dismiss

roots to *any* polynomial

3 views
Skip to first unread message

Jon

unread,
Nov 26, 2009, 1:32:12 PM11/26/09
to
http://jons-math.bravehost.com/rootformula.html

This solution for the roots of *any* polynomial requires some manipulation
of complex numbers. An example for the solutions to the Pentic is provided.


Dik T. Winter

unread,
Nov 27, 2009, 9:42:13 AM11/27/09
to

Take for your quintic a = b = 1, c = -2. Your formula gives:

x = {{3^(1/5) - 2}^(1/4)

which not even close to the actual root of 1.
--
dik t. winter, cwi, science park 123, 1098 xg amsterdam, nederland, +31205924131
home: bovenover 215, 1025 jn amsterdam, nederland; http://www.cwi.nl/~dik/

Heissenburger

unread,
Jun 18, 2010, 5:43:28 PM6/18/10
to
check out this free website
http://www.wolframalpha.com/

it (tries to) solves everything!
just type your question!

--- news://freenews.netfront.net/ - complaints: ne...@netfront.net ---

0 new messages