a[0] + a[1]x + a[2]x^2 + a[3]x^3 + ... + a[n]x^n = 0
x = { (C^((j-1)/n))*S }^(1/(n-j)) j=1,2,3,...,n-1
ALL SUMS ARE FROM p=1 to n
C = 1 - (a[0]*SUM a[p])/(SUM (a[p])^2)
S = (1/(5^(1/2)))*SUM{(D^(2n-2p))*(C^((2p-2)/n))}
D = -a[0]/SUM{a[p]*C^((p-1)/n)}
Jon Giffen