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multiples of 9

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makc.th...@gmail.com

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Oct 19, 2006, 3:30:36 AM10/19/06
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I have just noticed that for numbers like 9n, sum of difits is always
9. for example:

n 9n
1 9 obvious

2 18 1+8=9
3 27 2+7=9
4 36 3+6=9
5 45 4+5=9

6 54 5+4=9
7 63 6+3=9
8 72 7+2=9
9 81 8+1=9

10 90 obvious

how is this explained mathematically? could it be used somehow? perhaps
to speed up multiplication or something.

?

Virgil

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Oct 19, 2006, 3:44:43 AM10/19/06
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In article <1161243036.3...@b28g2000cwb.googlegroups.com>,
"makc.th...@gmail.com" <makc.th...@gmail.com> wrote:

Before the advent of electronic shortcuts to manual arithmetic, it was
widely used to check arithmetical operations, particularly
multiplications, in a technique called casting out nines.

You can google "casting out nines for a lot more that you probably will
ever want to know about the process.

me1...@gmail.com

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Oct 19, 2006, 8:36:36 AM10/19/06
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makc.th...@gmail.com wrote:
> I have just noticed that for numbers like 9n, sum of difits is always
> 9. [-SNIP-] how is this explained mathematically?

Your number X = A + 10B + 100C + ... + (10^d)D. If X is a multiple of
9, then X minus (9B + 99C + ... + (10^d - 1)D) gives us another
multiple of 9. After the subtraction, you have A+B+C+...+D, which is
the sum of the digits.

Bob H

makc.th...@gmail.com

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Oct 19, 2006, 11:37:43 AM10/19/06
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a ha! thanks man, i knew that must be simple.

i opened my calc and did 123x9, which is 1107, 1+1+0+7 = 9, and was
under impression that it is always 9, but then i did 321x9 :(

so it is actually sum of digits of sum of digits of. .... .. . . digits
of 9n = 9.

that's so cool that I almost have an erection. cant wait to tell my
mommy.

Arturo Magidin

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Oct 19, 2006, 11:40:46 AM10/19/06
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In article <1161272263.3...@k70g2000cwa.googlegroups.com>,

makc.th...@gmail.com <makc.th...@gmail.com> wrote:
>
>me1...@gmail.com wrote:
>> makc.th...@gmail.com wrote:
>> > I have just noticed that for numbers like 9n, sum of difits is always
>> > 9. [-SNIP-] how is this explained mathematically?
>>
>> Your number X = A + 10B + 100C + ... + (10^d)D. If X is a multiple of
>> 9, then X minus (9B + 99C + ... + (10^d - 1)D) gives us another
>> multiple of 9. After the subtraction, you have A+B+C+...+D, which is
>> the sum of the digits.
>
>a ha! thanks man, i knew that must be simple.
>
>i opened my calc and did 123x9, which is 1107, 1+1+0+7 = 9, and was
>under impression that it is always 9, but then i did 321x9 :(

Keep doing it until you get a single digit answer. Then that answer is
either 9 or 0 (and it is only 0 if you started by multiplying by 0...)

>so it is actually sum of digits of sum of digits of. .... .. . . digits
>of 9n = 9.

Yes.


--
======================================================================
"It's not denial. I'm just very selective about
what I accept as reality."
--- Calvin ("Calvin and Hobbes" by Bill Watterson)
======================================================================

Arturo Magidin
magidin-at-member-ams-org

mensa...@aol.com

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Oct 19, 2006, 12:34:40 PM10/19/06
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Of course, casting out 9's is just the tip of the iceberg.

See Slot Machine Arithmetic: Casting Out Cherries
<http://members.aol.com/rotanasnem/cherries/cherries.htm>

Prai Jei

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Oct 19, 2006, 6:18:30 PM10/19/06
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Arturo Magidin (or somebody else of the same name) wrote thusly in message
<eh869u$2tgm$1...@agate.berkeley.edu>:

>>i opened my calc and did 123x9, which is 1107, 1+1+0+7 = 9, and was
>>under impression that it is always 9, but then i did 321x9 :(
>
> Keep doing it until you get a single digit answer. Then that answer is
> either 9 or 0 (and it is only 0 if you started by multiplying by 0...)

You can play this game with multiplications also, in which case you *can*
get a zero answer even if the starting number is non-zero, e.g. 25 -> 10 ->
0.

This leads to a *very* uneven distribution of final numbers, with "0"
leading the field (since any intermediate number containing 0 promptly
leads to a final answer of 0) and even digits faring better than odd with
"1" being extremely rare.

The number 277,777,788,888,899 requires no less than 11 cycles before a
single digit (0) is reached. It is the smallest such number. No number
requiring more than 11 cycles is known - there are none up to 10^51.
--
Warning: keel away from child for hot bulb

Interchange the alphabetic letter groups to reply

Proginoskes

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Oct 19, 2006, 6:32:57 PM10/19/06
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You can't wait to tell your mommy that you almost have an erection?
What kind of sick bastard _are_ you?

--- Christopher Heckman

mensa...@aol.com

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Oct 19, 2006, 6:58:56 PM10/19/06
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Mother/son incest is a common category of porn site.

So they say.

>
> --- Christopher Heckman

Prai Jei

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Oct 22, 2006, 5:50:49 AM10/22/06
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Proginoskes (or somebody else of the same name) wrote thusly in message
<1161297176.9...@i42g2000cwa.googlegroups.com>:

>> that's so cool that I almost have an erection. cant wait to tell my
>> mommy.
>
> You can't wait to tell your mommy that you almost have an erection?
> What kind of sick bastard _are_ you?

He's not sick he's absolutely normal. It used to happen to me when I was a
kid.

makc.th...@gmail.com

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Oct 23, 2006, 3:10:24 AM10/23/06
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Prai Jei wrote:
> Proginoskes (or somebody else of the same name) wrote thusly in message
> <1161297176.9...@i42g2000cwa.googlegroups.com>:
>
> >> that's so cool that I almost have an erection. cant wait to tell my
> >> mommy.
> >
> > You can't wait to tell your mommy that you almost have an erection?
> > What kind of sick bastard _are_ you?
>
> He's not sick he's absolutely normal. It used to happen to me when I was a
> kid.

are you saying you havent had an erection ever since then?

Prai Jei

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Oct 24, 2006, 6:08:10 PM10/24/06
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makc.th...@gmail.com (or somebody else of the same name) wrote thusly in
message <1161587424.0...@i3g2000cwc.googlegroups.com>:

Not from the excitement of solving a maths problem, no.

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