Blast from the past!

[Corey White]

I dug up this old article I wrote about kabbalah and maths. I actually had
a typo in one of the equations, so I figured better off share it again...

I have a theory that numbers are just variables, and that just maybe there
could be more than one answer for any problem. So then I thought about
Kabbalah. Each letter in the Jewish system of Gemantria, has a unique
number. So I decided to try this with the english words we use for
numbers. I wrote a program that solved it, and then learned online that
we only use 16 letters of the alphabet, which means you couldn't assign
every letter an integer in all possible numbers. But who needs to do
that? All we need are the numbers 0 - 10. Which can actually have
multiple values, but here is one:

To do this each letter is given one unique number. The numerical values
for all the letters in a word are added together. So o+n+e=1, and t+w+o=2.
That's all there is too it!

Here is a chart with the solution:.

[ E, F, G, H, I, L, N, O, R, S, T, U, V, W, X, Z]
[-2,-6, 0,-7, 7, 9, 2, 1, 4, 3,10, 5, 6,-9,-4,-3]

(zero) = (-3 + -2 + 4 + 1)

(one) = (1 + 2 + -2)

(two) = (10 + -9 + 1)

(three) = (10 + -7 + 4 + -2 + -2)

(four) = (-6 + 1 + 5 + 4)

(five) = (-6 + 7 + 6 + -2)

(six) = (3 + 7 + -4)

(seven) = (3 + -2 + 6 + -2 + 2)

(eight) = (-2 + 7 + 0 + -7 + 10)

(nine) = (2 + 7 + 2 + -2)

(ten) = (10 + -2 + 2)

Next to prove that we can actually use this system:

(ten^(two))*three = (10 + -2 + 2)^(10 + -9 + 1) * (10 + -7 + 4 + -2 + -2)


(ten^(two))*three = ( 10^2 ) * 3

(ten^(two))*three = ( 100 ) * 3

(ten^(two))*three = 300

Finally:
We see if we can learn something new from this puzzle!