I am wondering if there has ever been discovered a mathematical formula in
which the exact location of any given card can be found in a stacked deck.
That is, how many cards from the top of the deck that the card is locataed.
The following conditions must be met:
1) The card stack CANNOT be a Si Stebbins or an "Eight Kings" type arrangement
in which the values and the suits rotate in a perfect cyclical fashion.
2) The mathematical formula must be one which will provide a specific location
for every single card, without any duplications.
For example--Suppose I ask a spectator to name a card. The spectator names,
say, the Jack of Spades. What I want to be able to do is to figure out the
location of that card from the top of the deck, by using a mathematical formula
which uses a combination of the value of the card, in this case Jack = 11, and
an arbitrary value assigned to its suit.
If anybody has any personal knowledge of this information, or of any sources I
can contact to locate it, I would be deeply appreciative. Thanks.
Dennis
The Classic Magic of Larry Jennings has some of this type of material.
There are several effects of this sort but they don't fulfil your
exact criteria. However, you won't be disappointed; it's one of the
best books out there.
Mig
Andy Leviss -- magkl...@aol.com
Check out my "Look Out World!" lecture and product line:
http://www.Andy-L.com/lookoutworld
I could have sworn that I had a little booklet years ago on all these tricks
you can do with a Si Stebbins stack and figuring out the position of any card
was one of them. Apparently, I have lost this little book.
For example, how can you figure out the position of, say, the Six of Clubs in a
Si Stebbins arrangement if you know that the Ace of Clubs is on top?
Isn't there a formula for this?
Any info on this would be deeply appreciated. Thanks.
Pee Y Chung
It's more practical to work from what card you know is on the
*bottom*.
There are two obvious ways. The one I would find the easiest is a two
step process:
First, determine where the first card of matchine suit is from the
top.
Then determine how far down the target is from that.
If the bottom card is the ace of clubs, you know the king of clubs is
the fourth card down. Now, subtract 6 from 13, giving 7. That's how
many clubs down *below* the king the 6 is. Multiply that by four, and
add it to the position of the king, giving 28 + 4 = 32.
The other way is to combine it all into one big formula...
Let:
Clubs = 0
Hearts = 1
Spades = 2
Diamonds = 3
Finding the first matching card from the top would be:
D_1 = Suit of target - Suit of bottom card modulo 4
If you get zero, that means the bottom card and the target card are
the same, and you can just work from the bottom card.
The value of the first matching card would be:
V_1 = Value of bottom card + (D_1 * 3) modulo 13
The distance from the first matching card to the target card, with VT
being the value of the target will be:
D_2 = (V_1 - VT modulo 13) * 4
And the total distance to the target card will be
D_1 + D_2
So, calling SB suit of the bottom card, ST the suit of the target, VB
the value of the bottom card, and VT the value of the target, and
expanding, you get:
(ST-SB mod 4) + ((VB + (ST-SB mod 4) * 3 mod 13) - VT mod 13) * 4
So, if you had the ace of clubs on the bottom, and wanted to find the
six of clubs:
(0-0 mod 4) + ((1 + (0-0 mod 4) * 3 mod 13) - 6 mod 13) * 4 =
0 + ((1 + 0 * 3 mod 13) - 6 mod 13) * 4 =
( 1 - 6 mod 13) * 4 =
(-5 mod 13) * 4 =
8 * 4 =
32
And there you have it.
Erdnase also describes a method that involves some mental counting,
but will work with the eight kings stack in the section on "The
Prearranged Deck". He also gives a great shuffle for use with a
stacked deck as "First Method" on page 159.
Best of luck,
Andru
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Basically you (or the spectator) cut the deck anywhere, look at the
bottom card in the stack just removed and instantly know the next card.
Cut the deck as many times as you want, look at the bottom card and
instantly know what the top one is.
You can spread the cards and no stack is obvious, the cards look
completely random.
-Leary-
Note: If you want a mechanical deck which lists where each card is
located in the deck, you can always go with a Deland deck. Don't EVEN
pull this deck out around a magician or you'll be laughed off the
planet.
Jim
Goodsell <titch...@btinternet.com> wrote in message
news:8k8aau$kv5$1...@uranium.btinternet.com...
yours for souls allways :) in Christ Bill ;)
<>< []xxxxxxxxx[]:::::::::::::::>
http://community.webtv.net/magic-bill
Just came back from my holidays and read your question.
There is a mathematical stack described in The Little Egypt Gazette, an
e-zine on the web, a couple of years ago. I didn't check it , but I believe
it is still on the net (www.littleegyptmagic.com-magic.html). If you can't
find it, mail me.
Rob.
Starcap 50 <star...@aol.com> schreef in berichtnieuws
20000707064326...@ng-fv1.aol.com...
L-
yours four souls allways:)
inChrist Bill the Christian Magician:)
<>< []xxxxxxxxx[]::::::::::::>
my web page is at http://community.webtv.net/magic-bill
Am I the only one here who doesn't understand this?
Is there an easier explantion of this somewhere?
Dennis
What is a "modulo"?
Dennis
>One more question.
>
>What is a "modulo"?
>
Dennis,
Its a mathematical term and principle best applied to math by
computer. Some of these guys amaze me at what they can do in their
heads. I guess I can blame old age.
Best Regards,
Ray
You can think of it as the remainder of a division. 23 modulo 4 is
3. Modulo 13 means you only have the numbers 0-12, and modulo 4 means
you only have the numbers 0-3.
Andru
--
Andru Luvisi, Programmer/Analyst