On 4/17/2019 5:24 PM, trader_4 wrote:
> On Wednesday, April 17, 2019 at 6:12:58 PM UTC-4, dpb wrote:
>> On 4/17/2019 4:50 PM, trader_4 wrote:
>> ...
>>
>>> IDK what well pumps you're looking at or where you get your prices,
>>> but a basic well pump can be had for $125 too. What well pump costs $1500?
>>> Even typical submersible costs less than half that. For something like
>>> this, can probably find low cost or used ones on Ebay too.
>>
>> Probably the cost of the snubber to fit a barrel... :)
>>
>> Seems like overkill to me for the purpose, though, too...guess depends
>> on just how big the rain barrel really is--just a 55-gal drum wouldn't
>> go all that far or last long.
>
> That's a very good point. Especially since they mentioned a sprinkler.
> One head is typically 2 GPM. If you have 3, the barrel will last less
> than 10 mins. And if you're trying to water turf, that amount is pointless.
> Most of that will just get it wet, barely start to penetrate, most will be lost
> to evaporation as it dries out, unless you can continue with another water
> source. If you do the math, to put down 0.5" of water over any reasonable
> area takes a lot of water. It's thousands of gallons to water my front lawn.
...
Indeed...well let's see
>> G2CF=@(g) 0.133681*g; % gal to cu-ft
>> A=20*20; G=55; % 20x20 sprinkler area, 55 gal drum
>> fnDPTH=@(h) A*12*h-G2CF(G); % vol over A of h less total volume G gal
>> d=fzero(fnDPTH,0.1) % how much can put on area A with 55 gal?
d =
0.0015
>>
So, assuming a 20x20 sprinkler area, 55 gal would be about 1.5
thousandths of an inch... :)
(Yes, it's solvable by simple straight algebra, but since we're
overthinking a problem here anyway, let's keep up the tradition...)
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