-> For instance y=root x is y=x^2 rotated 90 degrees clockwise.
Ex. How would I get the equation for a normal parabola with (0,0) vertex,
but opening in a diagonal direction such as towards (+3,+3)?
I realize this would no longer be called a function, because some values
would invariably overlap in ANY rotated parabola except those that open
Straight down and Straight up.
Thanks a lot!
Greg
too...@hurontel.on.ca
It is both mirroring x and y, AND rotating 90 degrees but I was looking for
the latter.
By the way, can't you simply use the notation y = +-(root x)? Where the plus
is right above the minus.
(Instead of uniting the negative and positive functions separately.)
Oh well
Greg
too...@hurontel.on.ca
One way to do a rotation is to replace each x by x*cos(a) + y*sin(a)
and simultaneously replace each y by -x*sin(a) + y*cos(a).
The resulting graph will be rotated counterclockwise through an
angle a from the original graph. The resulting equation will not
usually be the equation of a function.
--
Virgil
vm...@frii.com
original function: y = x^2
mirroring in x=y: x=y^2
y=+sqr(x) "united with" y=-sqr(x)
Jeroen Neve
Greg wrote in message ...