PLEASE HELP - Algebra Problem

[RCiancia]

A movie theater sold student tix for $3.25 and adult tix for $5.00. on
Saturday, the theater sold 16 more adult tix than student tix. If the total
sales totaled $740, how many of each kind were sold..

Thanks
RCia...@aol.com

[Richie]

In order to do this, you need to set up a system of equations. First define
two variables...ie.
s = # of student tickets sold
a = # of adult tickets sold

Next set up two different equations, one that represents the total number of
tickets sold(there were "s" amount of student tickets, and "a" amount of
adult, and together they equal all the tickets sold)
The second equation uses price( "s" tickets sold at a certain price, and "a"
amount sold at another, together they equal the total.)

Then just solve the system of equations

Richard

RCiancia <rcia...@aol.com> wrote in message
news:19991212132805...@ng-fr1.aol.com...

[Paul]

Here you go:

Let X=the number of student tickets sold

so the dollar amount of student tickets sold will be 3.25x
There were 16 more adult tickets sold than student tix so the dollar amt. of adult tickets is
5(x+16)

so here is the equation:
3.25x+5(x+16)=740
3.25x +5x +80 = 740
-80 = -80
================
8.25x = 660
x = 80

So there were 80 student tickets sold, and since there were 16 more adult tickets sold, 96
adult tickets were sold.

Check:

80 * 3.25 = $260 <==cash from student tix sales
96 * 5.00 = $480 <==cash from adult tix sales
====
$740 Total Sales, it works!

Take it easy - Paul

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[Leslie Wright]

> A movie theater sold student tix for $3.25 and adult tix for $5.00. on
> Saturday, the theater sold 16 more adult tix than student tix. If the total
> sales totaled $740, how many of each kind were sold..
>

Let A = number of adult tickets sold
Let S = number of student tickets sold

The word problem tells us that (and gives us the system of linear
equations):
325S + 500A = 74000
A = S + 16

Substituting the latter of these into the first gives

325S + 500(S + 16) = 74000
13S + 20(S + 16) = 2960
13S + 20S + 320 = 2960
33S = 2640
Therefore, S = 80
and A = 80 + 16 = 96

I have done two things that I am sure some math teachers might object
to: 1) I expressed all of the money amounts as cents, as I find it far
easier to deal with large whole numbers than small fractions or decimal
numbers, and 2) I started out expressing the problem as a system of two
equations in two unknowns. Some would argue that since the relationship
between the types of tickets sold is so simple, I shouldn't have
bothered with that.

Finally (I will tell you this before Stan does), PLEASE do not post the
exact same question more than once in short time span with a different
subject header. Irritates the heck out of the regulars.

Les