Everyone try to prove that electron cannot exist in the nucleus in
different methods. The Proof can be either or theoritical.
I am posting two Proof, one based on Schrodinger's Wave Equation and
one based on Heisenberg's uncertainity principle.
Looking Forward for your innovative proofs.
Regards
Tarun Ayitam
Moderator
Science and Sports
Electron is not static, it keeps moving. So KE not equal to zero.
Total Energy - Potential Energy not equal to 0
E - U =! 0 (=! means not equal to)
multiplying both sides by 8*pi*m/(h^2)
We get,
8*pi*m*(E-U)/(h^2) =! 0
- dell square =! 0
-(do ^2 si/do x) + (do ^2 si/ do y) + (do ^2 si/ do z) =! 0
(do ^2 si/do x) + (do^2 si/do y) + (do ^2 si/do z) =! 0
hence x, y or z cannot be zero.
Hence the position of the electron cannot be (0,0,0) i.e. the nucleus.
Hence Electron cannot lie in the nucleus.
If Electron exists inside the nucleus, position of the electron =
(0,0,0)
According to Heisenberg's Uncertainity principle.
dp * dx >= h/4pi
dx is equal to zero.
Then, this inequality doesnt hold good.
This is a contradiction to our assumption.
Hence our assumption is incorrect.
Hence electron doesnt exist in the nucleus.
This method's credit goes to my classmate in FIITJEE.
But i had a doubt in this method. dp is uncertainity in p and not p,
so dp.dx is not equal to zero. Hence, this method may not be correct.
2)same as jjthomson's failure, neutralisation of charges.
3)no explanation for sharing of e-, formations of gamma+and -, bond
theory is rejected then.
4)every particle starts repelleng other particle, since one portion of
the atom has either an e- or p+ at a side.
5)rutherfords alpha scattering exp....
6)zeemans stark effect.
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regards,
Divij
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