What's the right way to implement and export new custom hook?

[Brenda Bell]

I've implemented a new hook as follows (first source file for the hook and second one for the plugin):

import configparser

import logging

from airflow.utils import AirflowException

from airflow.hooks.base_hook import BaseHook

import snowflake.connector

def _parse_snowflake_config(config_file_name, profile=None):

    Config = configparser.ConfigParser()
    [snip]

class SnowflakeHook(BaseHook):

    def __init__(

            self,

            snowflake_conn_id='snowflake_default'):

        super(SnowflakeHook, self).__init__()
        [snip]

    def get_conn(self):

        snowflake_config = _parse_snowflake_config(self.snowflake_config_file, self.profile)

        connection = snowflake.connector.Connect(**snowflake_config)

from airflow.executors.base_executor import BaseExecutor

from airflow.hooks.base_hook import BaseHook

from airflow.models import  BaseOperator

from airflow.plugins_manager import AirflowPlugin

from flask import Blueprint

from flask.ext.admin import BaseView, expose

from flask.ext.admin.base import MenuLink

from snowflake_hook import SnowflakeHook

class SnowflakeOperator(BaseOperator):

    pass

class SnowflakePlugin(AirflowPlugin):

    name = "snowflake_plugin"

    operators = []

    flask_blueprints = []

    hooks = [SnowflakeHook]

    executors = []

    admin_views = []

    menu_links = []

Both files are in ${AIRFLOW_HOME}/plugins with permissions set to 0755. I relaunched airflow to pick up the new plugins and the both compiled (I see the .pyc's and there are no compilation errors in the console). I'm pretty sure they're being loaded because I did see syntax errors in the console before I corrected the bugs.

When I try to create a new connection, I don't see my hook listed. Am I misunderstanding how this works?