Field name Labels is invalid. Please check your spelling and casing. (line 65)

[Clive]

Hi guys

I know this has been asked before and resolved at the time as a bug in adwords script code itself, but I am encountering the above error again in the following code....(line 65 is the line beginning "while...")

var labelSelector = AdWordsApp.labels()

     .withCondition('LabelNames STARTS_WITH_IGNORE_CASE 20141112')

     .orderBy("LabelNames DESC");

  

var labelIterator = labelSelector.get();

while (labelIterator.hasNext()) {

   var label = labelIterator.next();

   Logger.log(Utilities.formatString('Currently working on label', label)); 

Please can you help?

Thanks

Clive

[Alexander Wang]

Hi Clive,

The issue is that "LabelNames" is not a valid field for LabelSelectors. Instead you just want to use "Name". Something like:

function main() {
  // Change prefix to what you want.
  var labelPrefix = 'b'
  var labelSelector = AdWordsApp.labels()
     .withCondition('Name STARTS_WITH_IGNORE_CASE ' + labelPrefix)
     .orderBy("Name DESC");

  var labelIterator = labelSelector.get();


  while (labelIterator.hasNext()) {
    var label = labelIterator.next();

    Logger.log(Utilities.formatString('Currently working on label %s', label.getName()));
  }
}

LabelNames is a valid condition for CampaignSelectors, AdGroupSelectors, AdSelectors, and KeywordSelectors. For more info on Labels, I recommend looking at some of our developer site documentation:

https://developers.google.com/adwords/scripts/docs/features/labels

https://developers.google.com/adwords/scripts/docs/examples/labels

https://developers.google.com/adwords/scripts/docs/solutions/labels

Let us know if you have any other questions/issues.

Cheers,

Alex

[Clive]

Alex

Thanks very much. I will give this a go.

Regards

Clive