Problem getting Label name

[di...@easyleads.com]

Hi,

I can't get LabelName, it's returned as null. I'm using java library v201509

LabelServiceInterface labelService = adWordsServices.get(adwordsSession, LabelServiceInterface.class);

Selector selector = new SelectorBuilder()

.fields(LabelField.LabelName)

.fields(LabelField.LabelId)

.fields(LabelField.LabelStatus)

.build();

LabelPage page = labelService.get(selector);

if (page.getEntries() != null) {

for (Label label : page.getEntries()) {

System.out.println("Label id " + label.getId() + ", label name " + label.getName() + ", label status " + label.getStatus());

}

}

I'm getting id and status, but name is null. If I add LabelField.LabelAttribute to the selector then also then status becomes null.

Thanks.

[Anthony Madrigal]

Hi,

When using the SelectorBuilder, each time you use .fields, it overrides the previous one, so in your case the Id is overriding the Name field. Some fields, such as Status, are returned whether you select them or not, which explains why Id and Status get returned.

In order to fix your issue, change your selector to the following:

Selector selector = new SelectorBuilder()

 .fields(LabelField.LabelName,LabelField.LabelId,LabelField.LabelStatus)
 .build();

Cheers,

Anthony

AdWords API Team

[di...@easyleads.com]

Thanks.

Stupid mistake of mine.