Proof of Remainder Theorem

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Dr. Atul Nischal

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May 19, 2015, 2:49:07 PM5/19/15
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The Remainder Theorem

Suppose p(x) is a polynomial of degree at least 1 and c is a real number. When p(x) is divided by xc the remainder is p(c).

 

 

Proof

 

Let’s first recall the division algorithm for polynomials.

 

Suppose d(x) and p(x) are nonzero polynomials where the degree of p is greater than or equal to the degree of d. There exist two unique polynomials, q(x) and r(x), such that

p(x) = d(x) q(x) + r(x),

where either r(x) = 0 or the degree of r is strictly less than the degree of d.

 

When a polynomial is divided by xc, the remainder is either 0 or has degree less than the degree of xc.

 

Since xc is degree 1, the degree of the remainder must be 0, which means the remainder is a constant.

 

Hence, in either case, p(x) = (xc) q(x) + r, where r, the remainder, is a real number, possibly 0.

 

It follows that

 p(c) = (cc) q(c) + r

        = 0 ´ q(c) + r

       = r

 

So, we get r = p(c) as required.

 

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