Please write a function that can deal with the case where the list is
unordered, even though the given input [1..10^n] is ordered. Don't
worry, it isn't hard, since lists have a sort method:
sage: v = [3,8,1,2,5]
sage: v.sort()
sage: v
[1, 2, 3, 5, 8]
>
> Thanks,
>
> Michael Snider
>
--
William Stein
Professor of Mathematics
University of Washington
http://wstein.org