https://groups.google.com/d/forum/sci.mathsci.mathMathematical discussions and pursuits.Google GroupsPentcho Valev2016-08-25T08:34:39Zhttps://groups.google.com/d/topic/sci.math/7WJ2OfISa7YEinstein Schizophrenic World: Emergent Space-timeSpacetime has emerged from Einstein's 1905 (false) light postulate - it can have no other origin: http://community.bowdoin.edu/news/2015/04/professor-baumgarte-describes-100-years-of-gravity/ "Special relativity is based on the observation that the speed of light is always the same, independenSimon Roberts2016-08-24T23:36:58Zhttps://groups.google.com/d/topic/sci.math/ZxqHXjoy_JIJamesJames is simple. Q.E.D.Simon Roberts2016-08-24T17:09:49Zhttps://groups.google.com/d/topic/sci.math/cST9JF1kVw0Leonhard Euler. My idol. Where did he go?Leonhard Euler (15 April 1707 – 18 September 1783) Euler sum that is related to the Riemann Zeta Function. Version 3.10 E(s) = [1 + 1/2^s + 1/3^s + 1/4^s + ....]. and s is a complex variable. Euler showed: E(s) = PRODUCT_p[1/( 1 - p^(-s))]. p is prime. E(s) = PRODUCT_p[p^s/( p^s - 1)].WM2016-08-24T13:33:53Zhttps://groups.google.com/d/topic/sci.math/jdVQ_tgQ1l0Limits of sequences of setsThe sequence of sets {n/n} has limit 1 if the fractions are evaluated. The sequence of sets {n/n} has limit { } if the fractions are not evaluated. Regards, WMmina_world2016-08-24T12:18:13Zhttps://groups.google.com/d/topic/sci.math/aF4wDtxrEvMLimit question..Hello. teacher~ It's been a long time. I have a question. lim{x->0} {cos(tan 4x)} / {tan 4x} = 1/0 = oo It's the wrong approach. Why?Pentcho Valev2016-08-24T10:59:48Zhttps://groups.google.com/d/topic/sci.math/gizFhtlm8oIEinstein's General Relativity: Deductive Theory or Empirical Concoction?Einstein informs the gullible world that his approach is deductive: https://www.marxists.org/reference/archive/einstein/works/1910s/relative/ap03.htm Albert Einstein: "From a systematic theoretical point of view, we may imagine the process of evolution of an empirical science to be a continuousSimon Roberts2016-08-24T10:57:02Zhttps://groups.google.com/d/topic/sci.math/oxxTWYC32-sA Proof of Fermat's Last Theorem (Version 3)I really don't understand what happened today. I am taking very little credit for "finding" the proof. -------------------------------------------------- Proof of Fermat's Last Theorem (Version 3) Statement: (1.) a^p + b^p + c^p = 0. Given: a, b, and c are non-zero pairwise co-primevasuin...@gmail.com2016-08-24T09:58:13Zhttps://groups.google.com/d/topic/sci.math/T3r5DH8WJjAHadoop Training In Bay AreaHadoop is a very common and powerful (raised, flat supporting surface) for working with data, but it can be a little hard to get a grip exactly on what it is and what it does. Hadoop Training In Bay Area It's a collection of software computer programs that are used to work with big data. HadoopJohn Gabriel2016-08-24T08:40:30Zhttps://groups.google.com/d/topic/sci.math/Mz-_jo69It8Cauchy was an idiot.Watch how I debunk the mainstream notion of limit in this video: https://www.youtube.com/watch?v=6roMXD4w3RY Mainstream morons hate that video because it exposes their ignorance, incompetence and stupidity. The idea of limit is a very ill-formed and failed attempt by Cauchy to fix Newton's andSimon Roberts2016-08-24T06:01:42Zhttps://groups.google.com/d/topic/sci.math/kFc4fd7HUgAf(s) = g(c - s) revisited. conjectures included.Conjecture: The following is never true for all x, f(x) = g(c - x). x is a real variable. c is a real non-zero constant. f and g are different functions of one real variable. f and g are defined for all x. f and g are different functions. ----------------------------------------Simon Roberts2016-08-24T05:44:54Zhttps://groups.google.com/d/topic/sci.math/CCE1tVd8B5ca^2 + b^2 = 0 (mod p)p is an odd prime, a and b are non zero integers. Can a^2 + b^2 = 0 (mod p) or a^2 = -b^2 (mod p) ? Under what conditions TRUE and under what conditions FALSE? Thank You. -Simon Roberts rete...@gmail.comSimon Roberts2016-08-24T05:07:46Zhttps://groups.google.com/d/topic/sci.math/4olppAYyepkEuler sum that is related to the Riemann Zeta Function.Version 3.5 E(s) = Sum_{1 to oo}[1 + 1/2^s + 1/3^s + 1/4^s + ....] and s is a complex variable. Euler showed: E(s) = PRODUCT_p[1/( 1 - p^(-s))]. p is prime. E(s) = PRODUCT_p[p^s/( p^s - 1)]. F(s) = PRODUCT_p[1/(p^s - 1)] = -/+E(-s) E(s) / [F(s)] = +/-E(s)/E(-s) = +/-PRODUCT_p[p^s] Let s =Dan Christensen2016-08-24T03:32:25Zhttps://groups.google.com/d/topic/sci.math/5fhfibtZ9p4A definition of the set of prime numbers without reference to the natural numbers?Can we list the essential properties of the set of prime numbers without any reference to the natural numbers, properties from which we might formally derive all of modern number theory as we know it? IIUC Jim Burns claims it is possible, but has yet to present them here. How about it Jim?John Gabriel2016-08-24T01:44:06Zhttps://groups.google.com/d/topic/sci.math/_9VLGB-duU4Despite all the attempts to libel and denigrate my work, the New Calculus flourishes: more subscribers, more views and likes.Well-formed knowledge always defeats ignorance. Find out more here: https://www.youtube.com/channel/UClBbBVLs3M-d3dNgU4Vop_A Now 81 subscribers and over 16000 in less than 9 months.Simon Roberts2016-08-24T01:42:20Zhttps://groups.google.com/d/topic/sci.math/ul4hDwdlsr8Please, for the love of "God", [quasi] fill in the blanks.Assume, (1.) a^p + b^p + c^p = 0 a, b, and c are non-zero pairwise co-prime. p is an odd prime. (2.a) (a+b) | (a^p + b^p = -c^p). (2.b) (a+c) | (a^p + c^p = -b^p). (2.c) (b+c) | (b^p + c^p = -a^p). From (2.a), (2.b), and (2.c) (3.) (a+b)(a+c)(b+c) | (abc)^p (4.) Y = (b+a)(b+c)(a+c)