No access to inner methods and members from a lambda?

[Christian Vogel]

Hi,

Say that I create an abstract class with a single abstract method, but with other members:

import org.junit.Test

abstract class Performer {

def perform() { println('hello!') } 

def abstract void hello()

}

And I try to create an instance by using a lambda [ | ] expression, I seem to be unable to access other members of this class ( perform() in this test case):

import org.junit.Test

class TestAbstract {

@Test def void test() {

work [| perform ] // gives error, perform is not accessible..

}

def void work(Performer p) {

p.hello

}

}

Why is this? The member is there in the created anonymous class in the created source code after all.

Christian

[Christian Vogel]

To answer my own question, is it because the ‘this’ of the created lambda is set to the current instance, to allow for closure programming?

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[Sebastian Zarnekow]

self.perform will do the trick. 'this' points to the enclosing instance where 'self' is the current anonymous lambda instance.

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[Christian Vogel]

great! thanks