uploading a file with a form ( without SQLFORM)

[Multiplery]

Hey folks,

I'm attempting to upload a file directly without the use of a SQLForm but rather the ordinary FORM.

From previous threads regarding the topic i figured my controller should look something like this:

[code]

def index():

    

    import shutil 

    form = FORM( 

            INPUT( _name="upload", _type="file"),

        INPUT( _type="Submit", _value="Upload" ))

    if form.accepts(request,session):

        if form.vars: 

         

           filename=request.vars.upload.filename

           file=request.vars.upload.file

           shutil.copyfileobj(file,open('/path'+filename,'wb')) 

    return dict (form = form)

[/code]

yet no file appears in the folder of my path. I'm not sure if the problem is with my code or maybe elsewhere, for example permission based. I'm using a raspberry with a raspiban os. i Already tried to start python as root user. 

Can someone spot a mistake in the code? has someone tried to run this on a debian based os and knows if its a permission problem? I'm aware of the potential dangers of the shutil.copyfileobj, so no worries about that.

Sincerely,

[Dave S]

Shouldn't you be passing the [relevant] request.post_vars to form.accepts() ?  See the top-level paragraph for FORM in chapter 7, and also

<URL:http://web2py.com/books/default/chapter/29/07/forms-and-validators#The-process-and-validate-methods>

/dps