Displaying request.vars

[Gael Princivalle]

Hello.

I would like to build an URL using request.args.

Something like that:

<a href="http://www.mydomain.com/index?{{=request.vars}}">
    Go
</a>

But the result is:

<a href="http://www.mydomain.com/index?&lt;Storage {'product_id': '8'}">
    Go
</a>

And it should be:

<a href="http://www.mydomain.com/index?product_id=8">
    Go
</a>

Someone have a solution?

Thanks, regards.

[Leonel Câmara]

{{import urllib}}

<a href="http://www.mydomain.com/index?{{=urllib.urlencode(request.vars)}}">
    Go
</a>

[Anthony]

Is it a web2py URL? If so, you can do URL(..., vars=request.vars).

Antony

[黄祥]

index.html

{{=A(_href = URL(vars = dict(product_id = request.vars) ) ) }}

best regards,

stifan

[Anthony]

On Thursday, March 5, 2015 at 6:53:47 AM UTC-5, 黄祥 wrote:

index.html

{{=A(_href = URL(vars = dict(product_id = request.vars) ) ) }}

"product_id" is already in request.vars (which acts like a dict), so no need to create a new dict with a "product_id" key.

Anthony

[Gael Princivalle]

Thanks a lot Leonel, it's exactly what I was searching for.

@Antony thanks but in this case it was not the current web2py url (a .load file), but another that calla the .load file.

[Anthony]

On Thursday, March 5, 2015 at 11:15:27 AM UTC-5, Gael Princivalle wrote:

Thanks a lot Leonel, it's exactly what I was searching for.

@Antony thanks but in this case it was not the current web2py url (a .load file), but another that calla the .load file.

As long as it is a web2py URL, you can and should use the URL function -- just specify the controller and function (and app if it's a different app):

URL('default', 'index', vars=request.get_vars, extension=False)

The extension=False argument will suppress the extension, so it won't propogate the .load extension.

Anthony