Hi all,
i am new to selenium RC and currently using Junit to run a testcase to
host my application (
https://10.55.34.201:8443/Applcationname/) and
entering to the login page but no luck, i got the below mentioned
error.But the same script runs successfully in IDE with Firefox
browser.
My understanding - As it can launch the firefox browser, so i suspect
it does not recognise the Application URl, So please suggest, if
anybody having any clue about this.
Find the below mentioned error,
com.thoughtworks.selenium.SeleniumException: XHR ERROR: URL =
https://10.55.34.201:8443/Applcationname/ Response_Code = -1
Error_Message = Request Error
at
com.thoughtworks.selenium.HttpCommandProcessor.throwAssertionFailureExceptionOrError(HttpCommandProcessor.java:
97)
at
com.thoughtworks.selenium.HttpCommandProcessor.doCommand(HttpCommandProcessor.java:
91)
at
com.thoughtworks.selenium.DefaultSelenium.open(DefaultSelenium.java:
353)
Regards,
Sashi.