On 27/09/16 04:35, Paul B. Andersen wrote:
> On 21.09.2016 Ralph Malcom Rabbidge wrote:
>
> On 24.09.2016 Dr. Wilson wrote:
> | Both your analogy and your reasoning is logically flawed. To explain the
> | Sagnac effect with the WBCE you must consider two such bicycles rotating
> | in opposite directions around their pedal axes.
> | The number of links that pass two non-rotating points on two cogs, as
> | viewed in the non-rotating frame, is then different.
>
> On 25.09.2016 Paul B. Andersen wrote:
> | I see.
> | If you have two equal chains on two sets of four cogwheels
> | arranged in a square, and these chains are rotating with
> | the same speed in opposite directions relative to the cogwheels,
> | and the square is rotating, then - according to the WBCE -
> | the number of links in the two chains will be different
> | because the number of links that pass two non-rotating points
> | on two cogs, as viewed in the non-rotating frame, is then different.
> |
> | You can see the two chains (red and blue) here:
> |
https://paulba.no/temp/Sagnac.pdf
>
> On 26.09.2016 Dr. Wilson wrote:
> | No, you are considering how things appear in the rotating frame....and
> | making a terrible mistake. If a Sagnac Gyro is considered in that frame,
> | the wavelength experiences an IMAGINARY change.... But I'm sure that is
> | far too hard for you....
>
> We can now consider the bogus BaTh refutation thoroughly unmasked
> by Henry's very clear explanation of why the number of links in
> a bicycle chain will change if the bicycle is rotated.
I knew this would be too hard for a laboratory attendant like yourself.
Paul, do you really think NUMBER is frame dependent?....just like your
colleague Bodkin does.
Paul, in the inertial frame, the path lengths of a sagnac gyro are
different during rotation.
Do you really believe you can change that fact just by converting to the
rotating frame? You cannot. You have made a gross error.
The answer is that the wavelength experiences an imaginary contraction
in one path and an elongation in the other.
Another way to look at that is to regard the (inertial frame) emission
point as having an imaginary movement in the rotating frame. It actually
moves backwards if PLOTTED in the rotating frame....DO YOU UNDERSTAND THAT?
> 'nuff said!
I think that should be now clear.
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