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(No-hair theorem * Buffon's needle) * black hole solutions

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David (Lord Kronos Prime) Fuller

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Apr 24, 2017, 12:35:16 PM4/24/17
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https://www.youtube.com/playlist?list=PLyQSN7X0ro203puVhQsmCj9qhlFQ-As8e

https://www.youtube.com/playlist?list=PLyQSN7X0ro2314mKyUiOILaOC2hk6Pc3j

https://en.wikipedia.org/wiki/No-hair_theorem

No-hair theorem ... Half of the Hairs are pointing "IN' with the Other Half Point "OUT".
This Cancels any "Gravitational Velocity" While Leaving the (Gravitational Pressure or Time Dilation)

http://vixra.org/abs/1310.0191

https://goo.gl/photos/ZAf1AgP3YFsKHUf76

https://goo.gl/photos/9Ve59ngYMCsXcgdV7

https://goo.gl/photos/an7Aq629eRYx3oZS6

https://goo.gl/photos/zRBcrygRSW2KLzH78

https://goo.gl/photos/sVVEJAtsAg8BF2mx8

https://goo.gl/photos/92k9erRifn2ibCFT7

https://goo.gl/photos/9vn6f8JrVnsYYf2c9

https://goo.gl/photos/KrzLMBhw6itWdQor9

https://goo.gl/photos/Bk21eqvNWb9DXYJN9

https://goo.gl/photos/5gpzGsh2SwZzmVM49

https://goo.gl/photos/X4YDy8YnfuiJYjr99

https://goo.gl/photos/ctfVZ2FUYq5GGvby8

https://goo.gl/photos/LKnjy9nf1VDeMuTu7

https://goo.gl/photos/73vBukiF2HqigoCX7

https://goo.gl/photos/jf5zqRT56DMjbdEP7



Buffon's needle
https://en.wikipedia.org/wiki/Buffon%27s_needle


No-hair theorem
https://en.wikipedia.org/wiki/No-hair_theorem



(No-hair theorem * Buffon's needle)= https://goo.gl/photos/9Ve59ngYMCsXcgdV7


Permeability (electromagnetism)
(4pi/10^7) / 4pi / 2 = https://goo.gl/photos/ZAf1AgP3YFsKHUf76 = 2/10^7 newtons

https://en.wikipedia.org/wiki/Permeability_(electromagnetism)


The ampère is that constant current which, if maintained in two straight parallel conductors of infinite length, of negligible circular cross-section, and placed one meter apart in vacuum, would produce between these conductors a force equal to 2 × 10−7 newton per meter of length

The no-hair theorem postulates that all black hole solutions of the Einstein-Maxwell equations of gravitation and electromagnetism in general relativity can be completely characterized by only three externally observable classical parameters: mass, electric charge, and angular momentum.[1] All other information (for which "hair" is a metaphor) about the matter which formed a black hole or is falling into it, "disappears" behind the black-hole event horizon and is therefore permanently inaccessible to external observers. Physicist John Archibald Wheeler expressed this idea with the phrase "black holes have no hair"[1] which was the origin of the name. In a later interview, John Wheeler says that Jacob Bekenstein coined this phrase.[2]

The first version of the no-hair theorem for the simplified case of the uniqueness of the Schwarzschild metric was shown by Werner Israel in 1967.[3] The result was quickly generalized to the cases of charged or spinning black holes.[4][5] There is still no rigorous mathematical proof of a general no-hair theorem, and mathematicians refer to it as the no-hair conjecture. Even in the case of gravity alone (i.e., zero electric fields), the conjecture has only been partially resolved by results of Stephen Hawking, Brandon Carter, and David C. Robinson, under the additional hypothesis of non-degenerate event horizons and the technical, restrictive and difficult-to-justify assumption of real analyticity of the space-time continuum.

David (Lord Kronos Prime) Fuller

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Apr 24, 2017, 1:40:00 PM4/24/17
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https://en.wikipedia.org/wiki/SI_electromagnetism_units


The ampere is that constant current which, if maintained in two straight parallel conductors of infinite length, of negligible circular cross-section, and placed one metre apart in vacuum, would produce between these conductors a force equal to 2e−7 newtons per metre of length


gravitational constant * 18828.6185437 newtons = 1.25663706e-6

gravitational constant * (137.217413413^2) newtons = 1.25663706e-6

gravitational constant * (137.03600^2) newtons = 1.25331649e-6

1 / ((G * (137.03600^2) newtons) / ((4 * pi) / (10^7))) = 1.00264943

1 / (1.00264943 - 1) = 377.439675704

((4pi) / (10^7)) / ((137.03600^2) newtons) = 6.69176248e-11

1.00264943 * (299792458*(4pi/10^7) - 1 = 376.725784626

David (Lord Kronos Prime) Fuller

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Apr 24, 2017, 2:01:58 PM4/24/17
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David (Lord Kronos Prime) Fuller

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Apr 24, 2017, 2:31:11 PM4/24/17
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No-hair theorem ...

Half of the Hairs are pointing "IN' with the Other Half Point "OUT".

This Cancels any "Gravitational Velocity" While Leaving the (Gravitational Pressure or Time Dilation)

https://goo.gl/photos/SNqhAUfovdhEY8Hy8

David (Lord Kronos Prime) Fuller

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Apr 25, 2017, 11:03:02 AM4/25/17
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((1.29609239e+26 meters) * (c^2) * 137.035999) / (2.39177670813e+55 kg) = 6.67407994e-11

((13.7 billion light years) * (c^2) * 137.035999) / (2.39177670813e+55 kg) = 6.67407995e-11

(13.7 billion light years * (c^2) * 137.035999) / G = 2.39177669e+55 kilograms

U = (G*M*m)/(distance of r * c^2)

(2*G*M*m) .. These are the Entropy Terms

(c^2 * r) ... These are the Energy Terms

David (Lord Kronos Prime) Fuller

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Apr 25, 2017, 11:16:21 AM4/25/17
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David (Lord Kronos Prime) Fuller

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Apr 25, 2017, 12:13:30 PM4/25/17
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(90 / (180 / pi)) / (((hbar / 137.03600)^2) * (c^2)) = 2.95117872e+55

David (Lord Kronos Prime) Fuller

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Apr 25, 2017, 12:31:37 PM4/25/17
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((137^2) * (c^2) * 2) / hbar = 3.1991631e-55 kg/s

David (Lord Kronos Prime) Fuller

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Apr 25, 2017, 12:48:33 PM4/25/17
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David (Lord Kronos Prime) Fuller

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Apr 25, 2017, 1:06:59 PM4/25/17
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(((137 * c)^2) * 4 * pi) / 3.1991631e+55 =
6.62607004e-34 m^2 / s^2
Dooh!


Now, the size of the observable universe is about 14 billion light years, and using the above value of density gives you a mass (dark and luminous matter) of about 3e-53 kg

((137 * (c^2)) * e) / hbar =
3.17380545e+53 s/kg

David (Lord Kronos Prime) Fuller

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Apr 25, 2017, 2:02:14 PM4/25/17
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1 / (((2 * 137.0359997 * G) / (hbar * 2pi * (c^3)))^0.5) = 0.987941041 m kg / s


((2pi * 137.0359997 * G) / hbar)^2 =
2.96933768e+53 m^2 kg^-4 s^-2

David (Lord Kronos Prime) Fuller

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Apr 27, 2017, 2:53:57 PM4/27/17
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((((c^2) * 6.67374768e-11) / (50 - 1))^2) * 6.67374768e-11 = 1 m^4 / s^4

((((c^2) * 6.67374768e-11) / (7^2))^2) * 6.67374768e-11 = 1 m^4 / s^4

https://goo.gl/photos/iNPZnqSa8SUgi6XC9

https://goo.gl/photos/2TkdjavECU8pd1Hg9

https://goo.gl/photos/8FEYpYj4stA9dYcu9

David (Lord Kronos Prime) Fuller

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Apr 27, 2017, 3:06:09 PM4/27/17
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David (Lord Kronos Prime) Fuller

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Apr 28, 2017, 10:41:14 AM4/28/17
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7 Axis truncated octahedral

(1.498408462835e10^(3 / 4)) * 7 = 299792458

1 / (1.498408462835e10 * gravitational constant) = 0.999950207

1 / 1.498408462835e10 = 6.6737477e-11

David (Lord Kronos Prime) Fuller

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Apr 28, 2017, 4:53:30 PM4/28/17
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1 / (0.1 / (((4 * pi) / 1e+16)^(3 / 4))) = 6.6743257e-11

G * (0.1 / (((4 * pi) / 1e+16)^(3 / 4))) = 0.999963183

David (Lord Kronos Prime) Fuller

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Apr 28, 2017, 5:00:32 PM4/28/17
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(0.1 / (((4pi) / 1e+16)^(3 / 4))) * 6.6737477e-11 = 0.99991339472

David (Lord Kronos Prime) Fuller

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Apr 28, 2017, 10:26:14 PM4/28/17
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1 / ((2.99781263e+8^(4/3)) / (7^(4/3))) = 6.67408e-11

1 / ((2.99792458e+8^(4 / 3)) / (7^(4 / 3))) =
6.6737477e-11

3 Euclidean Axis
4 Octahedral Axis

3+4 = 7 Axis

Two capacitive surfaces shaped into an infinite Schwartz P Minimal surface which is Toroidal just as is a magnetic field


David (Lord Kronos Prime) Fuller

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Apr 28, 2017, 10:29:34 PM4/28/17
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David (Lord Kronos Prime) Fuller

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Apr 28, 2017, 11:20:56 PM4/28/17
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G / (((4pi) / (1e+11^(4 / 3)))^(3 / 4)) = 0.999963183

((4pi) / (1e+11^(4 / 3)))^(3 / 4) = 6.6743257e-11

Looks like GravitoMagnetism

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