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Rydberg energy from FSC & Planck Pressure

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David (Kronos Prime) Fuller

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Apr 21, 2018, 7:48:33 PM4/21/18
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(1 / (((((((13.605609692 eV) / (c^2)) * G) / (c^2))^3) * ((c^7) / (hbar * (G^2)))) / (hbar^2))) / (137.03599917 * 29.9792458) = 1 m^2 kg

https://en.wikipedia.org/wiki/Rydberg_constant

What does Rydberg constant represent?
Rydberg constant. ... The Rydberg constant represents the limiting value of the highest wavenumber (the inverse wavelength) of any photon that can be emitted from the hydrogen atom, or, alternatively, the wavenumber of the lowest-energy photon capable of ionizing the hydrogen atom from its ground state.

Krono...@outlook.com

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Apr 21, 2018, 7:51:35 PM4/21/18
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((13.605609692eV/c^2)*G/c^2)^3 = 5.84266497e-186 m^3

Rydberg Energy Volume = 5.84266497e-186 m^3

David (Kronos Prime) Fuller

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Apr 21, 2018, 8:43:05 PM4/21/18
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(13.605609692 eV/hbar)^3 /c^5 *G * (137.03599917 * 29.9792458) = 1 m^-2 kg^-1

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Krono...@outlook.com

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Apr 21, 2018, 8:52:04 PM4/21/18
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1 / ((((((1 eV) / hbar)^3) / (c^5)) * G * ((137.03599917 kg) * (29.9792458 (m^2))))^(1 / 3)) = 13.6056097

(13.605609692 eV) / (c^2) = 2.42542021e-35 kilograms

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David (Kronos Prime) Fuller

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Apr 21, 2018, 10:00:46 PM4/21/18
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(1/G/1.37035999172e-5 kg/m^2*c^4 )^(1/3)*hbar /eV = 13.606

https://goo.gl/f993sf

1.37035999172e-5

137.035999172/1.37035999172e-5/1e7 = 1

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David (Kronos Prime) Fuller

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Apr 21, 2018, 11:45:11 PM4/21/18
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Mixing joules & eV is counter productive & silly 🙃

((1.37035999172e-5 kg m s)/c^4*G )/(hbar/2.179859e-18 Joule)^3 = 1

David (Kronos Prime) Fuller

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Apr 22, 2018, 3:22:08 AM4/22/18
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electron mass/2/ (13.605693 eV/(c/137.035999172)^2 = 1

13.605693eV/(10973731.568508 m^-1*(2pi*hbar)*c) = 1

Planck Pressure

(1 / (((((((13.605609692 eV) / (c^2)) * G) / (c^2))^3) * ((c^7) / (hbar * (G^2)))) / (hbar^2))) / (137.035999172 * 29.9792458) = 1 m^2 kg


(1/G/1.37035999172e-5 kg/m^2*c^4 )^(1/3)*hbar /eV = 13.605609692

((1.37035999172e-5 kg m s)/c^4*G )/(hbar/2.179858976e-18 Joule)^3 = 1

Rydberg

https://en.wikipedia.org/wiki/Rydberg_constant





David (Kronos Prime) Fuller

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Apr 22, 2018, 10:42:00 AM4/22/18
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1/((c^8/(hbar^3*G^2))*((((13.605609692 eV) / (c^2)) * G) / (c^2))^3) = 1.37035999172e-5 m kg s

(((((13.605609692 eV) / (c^2)) * G) / (c^2))^3) * (m^3) = 5.84266497e-186 m^3


(((((c^8) / ((hbar^3) * (G^2))))^0.125) * Boltzmann constant) / 8 = 0.997843512

David (Kronos Prime) Fuller

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Apr 22, 2018, 11:00:05 AM4/22/18
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David (Kronos Prime) Fuller

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Apr 22, 2018, 12:18:36 PM4/22/18
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https://en.wikipedia.org/wiki/Perfect_fluid

https://en.wikipedia.org/wiki/Fluid_solution#Special_cases

The last two are often used as cosmological models for (respectively) matter-dominated and radiation-dominated epochs. Notice that while in general it requires ten functions to specify a fluid, a perfect fluid requires only two, and dusts and radiation fluids each require only one function. It is much easier to find such solutions than it is to find a general fluid solution.

Among the perfect fluids other than dusts or radiation fluids, by far the most important special case is that of the static spherically symmetric perfect fluid solutions. These can always be matched to a Schwarzschild vacuum across a spherical surface, so they can be used as interior solutions in a stellar model. In such models, the sphere, where the fluid interior is matched to the vacuum exterior is the surface of the star, and the pressure must vanish in the limit as the radius approaches r = r0

However, the density can be nonzero in the limit from below, while of course it is zero in the limit from above. In recent years, several surprisingly simple schemes have been given for obtaining all these solutions.

David (Kronos Prime) Fuller

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Apr 22, 2018, 12:55:11 PM4/22/18
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Particles should be classified by Aether Displacement Volume

Not MeV

(2*electron mass*G/c^2)^3 = 2.47632111e-171 m^3

(2*2.176470e-8 kg*G/c^2)^3 = 3.37752094e-104 m^3



((((c^7) / (hbar * (G^2))) / pascals) * (((2 * electron mass * G) / (c^2))^3)) / (m^3) = 1.14734205e-57

((((c^7) / (hbar * (G^2))) / pascals) * (((2 * (2.176470e-8 kg) * G) / (c^2))^3)) / (m^3) = 1.56489067e10

(((((c^7) / (hbar * (G^2))) / pascals) * (((2 * (2.176470e-8 kg) * G) / (c^2))^3)) / (m^3)) * G = 1.04442055

David (Kronos Prime) Fuller

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Apr 22, 2018, 1:15:52 PM4/22/18
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Particles should be classified by Aether Displacement Volume

Not MeV

(((2 * (1 kg) * G) / (c^2))^3) = 3.27597059e-81 m^3


(((((c^7) / (hbar * (G^2))) / pascals) * (((2 * (1 kg) * G) / (c^2))^3)) / (m^3)) * (2pi * hbar) = 1.0057313


((((2 * (1 kg) * G) / (c^2))^3) / (((hbar / c) * (137.035999172 (kg^(-1))))^2))^2 = 1.98755658 m^2
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David (Kronos Prime) Fuller

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Mar 23, 2020, 9:21:54 AM3/23/20
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Rydberg Volume

(2.4263102367E-12 m)*10973731.568508 m^(-1))^3*hbar/(electron mass) = (13.6388817 eV)


(10973731.568508 m^(-1))^3/( 13.6388818 eV)*hbar/2pi*c^2 = (9.1224509E+20 pascals)

(((2pi) * 9.1224509E+20 pascals * ((2.4263102367E-12 m)^3)) / (c^2)) = electron mass

(Planck length * 1.50122737e+23) / meter = 2.42632627e-12

1.50122737E+23 / (((((c^7) / (hbar * (G^2))) * (Planck Length^3)) / (c^2)) / hbar) = 0.000727394316 m^2 / s


(((8^0.5) * 6.5248935)^0.25) / Boltzmann constant = 1.50122737e+23 m-2 kg-1 s2 K


1 / (((planck length * c * electron mass) / hbar) / (2 * pi)) = 1.50121745e+23

2* 137.035546366^2* 10973731.568508*(((((8^0.5) * 6.5248935)^0.25) / Boltzmann constant * planck length) = 1

1/((10973731.568508 m^-1)*(2.42632627e-12 m)*2)^0.5 = 137.035546366

((((8^0.5) * 6.5248935)^0.25) / Boltzmann constant * planck length) = 2.42632627e-12

Ross A. Finlayson

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Mar 26, 2020, 8:26:37 PM3/26/20
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Aether displacement volume: displacement in super-gravity space-time.

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