How to pass a function with implicit argument to a high-order function with full type signature (A => I => B)?

[Jianshi Huang]

I need to write a function that converts a function that takes an implicit argument of I to a function that takes an implicit argument of K (where I can be implicitly converted from K).

So the function type signature looks like:

  lift[A, B, I, K <% I](f: A => I => B): A => K => B

However, when I write

  lift(fn)

Scala reports "Could not find implicit value for fn ..."

Will Scala automatically curry fn to A => B by applying the implicit argument? How can I achieve my goal then?

Thanks

--

Jianshi Huang

LinkedIn: jianshi
Twitter: @jshuang
Github & Blog: http://huangjs.github.com/

[Naftoli Gugenheim]

Can you show fn?

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[Jianshi Huang]

Sure.

  def fn(id: String)(implicit qe: GraphQueryExecutor): Int = {

    ...

  }

Jianshi

[Stephen Compall]

On Mon, 2014-11-17 at 15:34 +0800, Jianshi Huang wrote:
> lift[A, B, I, K <% I](f: A => I => B): A => K => B
>
> However, when I write
>
> lift(fn)
>
> Scala reports "Could not find implicit value for fn ..."
>
> Will Scala automatically curry fn to A => B by applying the implicit
> argument? How can I achieve my goal then?

No, I don't think this will infer.


--
Stephen Compall
"^aCollection allSatisfy: [:each|aCondition]": less is better