SPARQL Querying in rdflib

[vsj...@gmail.com]

Hi,

I am trying to run a sparql query through rdlfib. I just want my query to return the class/subclass name without the URI. Is there any built-in function in rdflib that does that? I just want to scrap away the URI part. I know I can always use a regex but was wondering if there is anything in the library that helps me do that without having to do regex?

Let me know if you didn't get what I am saying. I can post the code if you need me to.

Thanks,
Uthej

[Gunnar Aastrand Grimnes]

The part you want is called hte "localname" - and this function will
get it for you:
http://rdflib.readthedocs.org/en/latest/apidocs/rdflib.html?highlight=split_uri#rdflib.namespace.split_uri

(if you want to get fancy you can expose that function as a custom
sparql function in rdflib, you wont have to post-process your query
results)

Note that if you consume data you do not have complete control over,
there is no-one forcing anyone to have sensible local-names for their
URIs, they are not really for human consumption, and some will just a
random identifier (Freebase data, i'm looking at you...)

A safer solution is to do an extra triple pattern for the rdfs:label
of whatever you're querying for.

- Gunnar

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[vsj...@gmail.com]

Thanks Gunnar, Appreciate the help. But here is the thing. I can't seem to understand the approach you are suggesting with the rdfs:Label tag. Here is the query that I am trying to run against the owl file:


SELECT ?Action
WHERE { alfredowl:Sad rdf:type alfredowl:Mood .
alfredowl:Sad alfredowl:possible ?Action }

Now weirdly enough this query in Protege returns just the label names without the URI. But somehow rdflib doesn't do that. The only difference I see is that in protege query engine I have to define the prefix but since I am parsing the xml from a local path in my code and my xml already has alfred ns defined, I don't have to do it here. Any which way how do you suggest I change this query to get only the labels?