#interaction hamiltonian
H_i=e1g1*omega2*(sigma_g1e1.dag()+sigma_g1e1)+
e1g2*omega1*(sigma_g2e1.dag()+sigma_g2e1)
H_b=(uB)*(-sigma_g1g1+0*sigma_e1e1+sigma_g2g2)
H=H_i+H_b
(from Appendix C)
#system hamiltonian
H=(-delta_min)*(sigma_ee-sigma_gg)+(phi)*(sigma_ee-sigma_uu)+
omega1*(sigma_ge+sigma_ge.dag())+omega2*(sigma_ue+sigma_ue.dag())
(from Appendix B)
The first piece of code uses interaction hamiltonian, and the second uses Schrodinger picture one.
Question One: would the two hamiltonians (if they are describing the same system) give the same physical results (expectation values)?
Question Two: In the second case, I suppose the operator sigma_ue is fast varying (not in the rotating frame). Shouldn't such fast varying behavior be cancelled by an exponential (provided by the external laser) in the Hamiltonian? I mean something like this: omega2 * sigma_ue * exp(i * \omega_2 * t).