Loop count parfor

[vali...@gmail.com]

Hi,

I have a simple question (since I am not skilled with python), is there a simple way to implement a loop count when I use parfor?

Thanks!

Pol

[Morgan Hedges]

Hi Pol,

do you mean that you want to keep track of how many iterations of your loop have been completed?

If that's what you mean, then the simplest thing I usually do is just make the called function print out a '*' or a relevant number

e.g.

import sys

import qutip as q

import time

def f(a):

    #do something with a

    time.sleep(1)

    print "*",

    sys.stdout.flush()

q.parfor(f, arange(10))

Then I get *'s appearing as each function call finishes.

Of course there's fancier things one can do too.

Is that what you meant?

Morgan

[vali...@gmail.com]

Hi Morgan,

Thanks for helping out! What you describe is what I meant, except I would like a counter. Usually on a for loop I can put something like i = i +1 and then print(i) at the end of the loop. But for some reason that doesn't work with parfor.
Any ideas?

Best,

Pol

[Paul Nation]

Pass an extra arg and set it with arange(N) where N is the the number of loops. Then print at the end of the func that you passed. 

Paul

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[Pol Forn Diaz]

Hi Paul,

Thanks for your advice!

In the end I did the following:

def task(args):

    m, omega = args

    count = arange(m)
    print("Step # " + str(count[-1:]) + "/" str(len(omega_list)))

    ...

Although the output is something like "Step # [45]/100", I would like to get rid of the [] but I can live with that.


Best,

Pol

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