RE: [Q] q.delay(x, t) vs. q.delay(t).thenResolve(x)

[Domenic Denicola]

You may have run into The Great Unhandled Rejected Promise Bug of 2013:

https://github.com/kriskowal/q/issues/238

Thankfully a kindly contributor fixed that in master, and we'll be releasing a bugfix release shortly. If you try the latest version from

https://rawgithub.com/kriskowal/q/master/q.js

does that fix the problem?

---

From: q-con...@googlegroups.com [q-con...@googlegroups.com] on behalf of David Jeschke [djes...@gmail.com]
Sent: Monday, May 13, 2013 13:00
To: q-con...@googlegroups.com
Subject: [Q] q.delay(x, t) vs. q.delay(t).thenResolve(x)

I would have thought that q.delay(x, t) would be equivalent to q.delay(t).thenResolve(x) however I found a difference when x is a rejected promise. Specifically,

var q = require('q');
q.delay(100).then(function() { return q.reject(new Error('foo')); }).fail(function(err) {});

will exit without error, while:

var q = require('q');
q.delay(q.reject(new Error('foo')), 100).fail(function(err) {});

will exit with:

Unhandled rejected promise: Error: foo
    at Object.<anonymous> (/test1.js:2:18)
    at node.js:901:3
From previous event:
    at Object.<anonymous> (/test1.js:2:3)
    at node.js:901:3

Is this a bug in Q or in my understanding? Thanks!

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[David Jeschke]

Thanks for the quick response, Domenic. I just tried it and unfortunately the result is the same. I have opened a new case for it:

https://github.com/kriskowal/q/issues/292