Abhishek Jha
Apr 24, 2014, 4:56:32 AM4/24/14
to orient-...@googlegroups.com
Hey ,
I am using ORIENTDB - 1.7.RC2
Blueprint - 2.6.0 - SNAPSHOT
When I am doing this :
OrientGraphQuery graphQuery = (OrientGraphQuery) graph.query();
Vertex base = null;
if(!graphQuery.labels(associationEntity.getType().toString()).has("value",associationEntity.getValue()).vertices().iterator().hasNext()) {
base = graph.addVertex("class:"+associationEntity.getType().toString(),"value",associationEntity.getValue());
}
else {
base = graphQuery.labels(associationEntity.getType().toString()).has("value", associationEntity.getValue()).vertices().iterator().next();
}
OrientGraphQuery newGraphQuery = (OrientGraphQuery) graph.query();
Vertex connected = null;
if(!newGraphQuery.labels(connectedVertexes.getType().toString()).has("value",connectedVertexes.getValue()).vertices().iterator().hasNext()) {
connected = graph.addVertex("class:"+connectedVertexes.getType().toString(),"value",connectedVertexes.getValue());
}
else {
connected = newGraphQuery.labels(connectedVertexes.getType().toString()).has("value",connectedVertexes.getValue()).vertices().iterator().next();
}
As you can see for both the vertices I am using different instance of GraphQuery. Then results are :
As you can see vertices aren't repeated.
But then if i change it to,
OrientGraphQuery graphQuery = (OrientGraphQuery) graph.query();
Vertex base = null;
if(!graphQuery.labels(associationEntity.getType().toString()).has("value",associationEntity.getValue()).vertices().iterator().hasNext()) {
base = graph.addVertex("class:"+associationEntity.getType().toString(),"value",associationEntity.getValue());
}
else {
base = graphQuery.labels(associationEntity.getType().toString()).has("value", associationEntity.getValue()).vertices().iterator().next();
}
Vertex connected = null;
if(!graphQuery.labels(connectedVertexes.getType().toString()).has("value",connectedVertexes.getValue()).vertices().iterator().hasNext()) {
connected = graph.addVertex("class:"+connectedVertexes.getType().toString(),"value",connectedVertexes.getValue());
}
else {
connected = graphQuery.labels(connectedVertexes.getType().toString()).has("value",connectedVertexes.getValue()).vertices().iterator().next();
}
Basically if i use same instance of graph query, then results are :
Here you can see vertices are coming as different. Basically not that I wanted, because I want that if vertex exists, I should use it rather than creating a copy of it in graph.
Please Help !!!
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