Sending a function to background in Async

[Paolo Donadeo]

When writing a daemon, using the standard Unix module, I usually send the "main" function to background using the classical double-fork technique:

match fork () with

| 0 -> if fork () <> 0 then exit 0;

      (* do whatever the child should do *)

| _ -> wait ();

      (* do whatever the parent should do *)

(source code stolen from Unix system programming in OCaml)

In Async of course this don't work. How can I achieve the same result?

BTW, I'm still writing in the Core mailing list about Async, is it ok?

--

Paolo

[Malcolm Matalka]

I believe Async or Core comes with a daemonize module you can use to
accomplish this.

Alternatively you can do your forking and everything before running the
scheduler, so old school rules apply there.

And I think 'Core' referrers to the 'Core Suite', of which Async is a
member.

Paolo Donadeo <p.do...@gmail.com> writes:

> When writing a daemon, using the standard Unix module, I usually send the
> "main" function to background using the classical double-fork technique:
>

> *match fork () with*
> *| 0 -> if fork () <> 0 then exit 0;*
> * (* do whatever the child should do *)*
> *| _ -> wait ();*
> * (* do whatever the parent should do *)*
>
> *(source code stolen from *Unix system programming in OCaml
> <http://ocamlunix.forge.ocamlcore.org/processes.html>*)*

>
> In Async of course this don't work. How can I achieve the same result?
>
> BTW, I'm still writing in the Core mailing list about Async, is it ok?
>
>
> --

> *Paolo*

[David House]

Indeed, you should use Core.Std.Daemon.daemonize. Incidentally, this module is in core and not async because you must do this before starting the async scheduler.

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[Paolo Donadeo]

Thanks!

--

Paolo