XSLT transform with params

[Jud]

I'm confused by the documentation around calling xslt transform() with
params.

I'm calling xslt.transform(doc), ['foo', 'bar']), but referencing $foo
in my xslt (e.g. <xsl:value-of select="$foo"/>) yields nothing. How is
that array supposed to be formatted?

[Mike Dalessio]

Without an example script I can't be sure (hint, hint), but I think I know what the issue is here.

Please try quoting the parameters passed to transform(). Either of the following would work:

xslt.transform(doc, Nokogiri::XSLT.quote_params(['foo', 'bar']))

or

xslt.transform(doc, Nokogiri::XSLT.quote_params('foo' => 'bar'))

I've added a new test case to master demonstrating that this is the way to call it:

http://github.com/tenderlove/nokogiri/blob/master/test/test_xslt_transforms.rb#L59

Cheers.

--
mike dalessio
mi...@csa.net

[Judson Valeski]

the quote_params did it. perfect. thanks!

Jud

[Honza Kotrs]

Perfect, still relevant today.;) Thanks!

Dne úterý 10. listopadu 2009 13:08:30 UTC+1 Mike Dalessio napsal(a):