mod_gpcm <- mirt(itemDf, 1, itemtype = 'gpcm', verbose = FALSE)
> coef(mod_gpcm, simplify=TRUE)$items a1 ak0 ak1 ak2 ak3 d0 d1 d2 d3itm1 2.133 0 1 2 3 0 -1.413 -4.609 -8.655itm2 2.638 0 1 2 3 0 -2.536 -7.369 -12.187itm3 1.131 0 1 2 3 0 -0.163 -1.097 -2.139itm4 1.831 0 1 2 3 0 0.267 -1.640 -4.142itm5 1.580 0 1 2 3 0 -1.339 -3.584 -6.247itm6 1.665 0 1 2 3 0 -2.501 -5.536 -8.320itm7 1.938 0 1 2 3 0 -1.590 -4.476 -7.913itm8 1.920 0 1 2 3 0 -3.098 -7.467 -11.323itm9 2.107 0 1 2 3 0 -5.176 -11.446 -17.713
> coef(mod_gpcm, simplify=TRUE, IRTpars = TRUE)$items a b1 b2 b3itm1 2.133 0.663 1.498 1.897itm2 2.638 0.961 1.832 1.826itm3 1.131 0.144 0.826 0.922itm4 1.831 -0.146 1.041 1.366itm5 1.580 0.848 1.421 1.685itm6 1.665 1.502 1.823 1.672itm7 1.938 0.820 1.490 1.774itm8 1.920 1.614 2.276 2.009itm9 2.107 2.457 2.976 2.975
> head(fscores(mod_gpcm, full.scores = FALSE))
Method: EAP
Empirical Reliability:
F1 0.791 itm1 itm2 itm3 itm4 itm5 itm6 itm7 itm8 itm9 F1 SE_F1[1,] 0 0 0 0 0 0 0 0 0 -1.11835765 0.6541271[2,] 0 0 0 0 0 0 0 1 0 -0.48372235 0.5046332[3,] 0 0 0 0 0 0 1 0 0 -0.47914656 0.5035579[4,] 0 0 0 0 0 0 2 0 0 -0.07728942 0.4132801[5,] 0 0 0 0 0 0 2 2 0 0.42370274 0.3194128[6,] 0 0 0 0 0 1 0 0 0 -0.55063076 0.5204260
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Phil
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Thanks for the super fast response. I must admit I feel better knowing that I really was pretty close.Can I ask, is it possible to obtain the scores from the coefficients? This is just to help my understanding in linking them together. Happy to go read a reference if you can point me to one that answers this question.
I've been reading on-line tutorials and journal articles all over the place, and while it seems to me that the ultimate reason we want to use IRT is to estimate scores, that last step gets left off (I presume that most authors assume it is obvious and it probably is to most readers).
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