custom serializer issue

[Aaron Weber]

I'm trying to implement a simple serializer to use with my custom class.

I know my class can be serialized to JSON (I have done it elsewhere), so I thought this would be an easy way to go.  However, on startup, when it is referenced as a .valueSerializer() , I get:

java.lang.IllegalArgumentException: Not serializable: class com.x.y.ext.JSONMapSerializer$2

at org.mapdb.SerializerBase.assertSerializable(SerializerBase.java:1482)

at org.mapdb.DB.createHashMap(DB.java:415)

at org.mapdb.DB$HTreeMapMaker.make(DB.java:216)

at org.mapdb.DB$HTreeMapMaker.makeOrGet(DB.java:222)

Not sure why.  The actual code is as follows:

    public static final Serializer<Favorites> FAVORITES_SERIALIZER = new Serializer<Favorites>()

    {

        @Override

        public void serialize(DataOutput dataOutput, Favorites favorites)

                throws IOException

        {

            Gson gson = new Gson();

            dataOutput.writeUTF(gson.toJson(favorites));

        }

        @Override

        public Favorites deserialize(DataInput dataInput, int i)

                throws IOException

        {

            Gson gson = new Gson();

            return gson.fromJson(dataInput.readUTF(), Favorites.class);

        }

        @Override

        public int fixedSize()

        {

            return 0;

        }

    };

It's probably not tremendously fast, but I don't need it to be in my case...just need it to work. :)

Thanks for any hints/tips/tricks!

-AJ

[Igor Castang]

a lot of versions of MapDB require the serializer class itself to be serializable. I forget if it's the case for the 2.0.X and 3.0.X branch, but I am pretty sure it's a need for any 1.0.X branch.
You should try to use a non anonymous class and make it implement serializable and try again.

regards

[Jan Kotek]

Yes, that is correct. Your serializer should be standalone class and implement Serializable interface.