Count me in.
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So a bit better
On Wed, Jul 19, 2017 at 10:13 AM, Patrick Joyce <12n...@gmail.com> wrote:
I'm interpreting that as the probability of it being a possibility is greater than 50%.
As for me, I'll just answer 2*e/(Pi^2).
On Wednesday, July 19, 2017 at 9:28:52 AM UTC-4, Tim Miller wrote:i am a most likely maybe
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Sadly, I did the exact same thing… (Didn’t post the results though…)
From: lv...@googlegroups.com [mailto:lv...@googlegroups.com]
On Behalf Of David Ortiz-Grob
Sent: Wednesday, July 19, 2017 11:52 AM
To: lv...@googlegroups.com
Subject: [EXT] Re: {LVL1} Dinner with Mike - Going Away Party
So a bit better
On Wed, Jul 19, 2017 at 10:13 AM, Patrick Joyce <12n...@gmail.com> wrote:
I'm interpreting that as the probability of it being a possibility is greater than 50%.
As for me, I'll just answer 2*e/(Pi^2).
On Wednesday, July 19, 2017 at 9:28:52 AM UTC-4, Tim Miller wrote:i am a most likely maybe
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Sadly, I did the exact same thing… (Didn’t post the results though…)
From: lv...@googlegroups.com [mailto:lv...@googlegroups.com] On Behalf Of David Ortiz-Grob
Sent: Wednesday, July 19, 2017 11:52 AM
To: lv...@googlegroups.com
Subject: [EXT] Re: {LVL1} Dinner with Mike - Going Away Party
So a bit better
On Wed, Jul 19, 2017 at 10:13 AM, Patrick Joyce <12n...@gmail.com> wrote:
I'm interpreting that as the probability of it being a possibility is greater than 50%.
As for me, I'll just answer 2*e/(Pi^2).
On Wednesday, July 19, 2017 at 9:28:52 AM UTC-4, Tim Miller wrote:i am a most likely maybe
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