Big table, numerate positions

Maciej Bąk

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Aug 26, 2016, 2:46:00 AM8/26/16

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HI,

Im rendering quite big table ( over 100 positions ).

In each I have <td class="position"></td>

Is it possible to somehow make working :

(1.to(114).map(num => ".position" #> num)) ?

Maciej Bąk

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Aug 26, 2016, 4:58:37 AM8/26/16

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I tried also "#appUserStatTbl *" #> (1.to(114).map(num => ".position *" #> num.toString)) but crap it renders table 114 times :(

Diego Medina

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Aug 26, 2016, 7:42:40 AM8/26/16

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you were really close!

try

"#appUserStatTbl" #> (1.to(114).map(num => ".position *" #> num.toString)) but crap it renders table 114 times :(

I just removed the * after #appUserStatTbl

Thanks

Diego

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Maciej Bąk

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Aug 26, 2016, 8:03:40 AM8/26/16

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Then it generated 114 times whole table :(

def renderNums = "#appUserStatTbl" #> (1.to(114).map(num => ".position *" #> num.toString))

def sendSnapshot(): Unit = {
  val html = Templates("admin" :: "app" :: "statistics" :: Nil).getOrElse(<span>Template Not found</span>)
  val out = (renderNums(Statistics.listStatistics(html))).toString

<div class="l:Statistics.listStatistics">

    <h3>User Statistics - <span name="generation-date">Date and Time</span></h3>

    <center>
        <table id="appUserStatTbl" class="tablesorter" style="width: 80%" border="1" >
            <thead>
            <tr>
                <th>Position</th>
                <th>Statistic</th>
                <th>Value</th>
            </tr>
            </thead>
            <tbody>
            <tr>
                <td class="position"></td>

W dniu piątek, 26 sierpnia 2016 13:42:40 UTC+2 użytkownik fmpwizard napisał:

you were really close!

try

"#appUserStatTbl" #> (1.to(114).map(num => ".position *" #> num.toString)) but crap it renders table 114 times :(

I just removed the * after #appUserStatTbl

Thanks

Diego

On Fri, Aug 26, 2016 at 4:58 AM, Maciej Bąk <maciej...@gmail.com> wrote:

I tried also "#appUserStatTbl *" #> (1.to(114).map(num => ".position *" #> num.toString)) but crap it renders table 114 times :(
W dniu piątek, 26 sierpnia 2016 08:46:00 UTC+2 użytkownik Maciej Bąk napisał:
HI,

Im rendering quite big table ( over 100 positions ).
In each I have <td class="position"></td>
Is it possible to somehow make working :
(1.to(114).map(num => ".position" #> num)) ?

--
--
Lift, the simply functional web framework: http://liftweb.net
Code: http://github.com/lift
Discussion: http://groups.google.com/group/liftweb
Stuck? Help us help you: https://www.assembla.com/wiki/show/liftweb/Posting_example_code

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Juan Jose Olivera

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Aug 26, 2016, 8:06:19 AM8/26/16

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Try this

def renderNums = "#appUserStatTbl" #> (1.to(114).map(num => ".position *" #> num.toString))

def sendSnapshot(): Unit = {
  val html = Templates("admin" :: "app" :: "statistics" :: Nil).getOrElse(<span>Template Not found</span>)
  val out = (renderNums(Statistics.listStatistics(html))).toString

<div class="l:Statistics.listStatistics">

    <h3>User Statistics - <span name="generation-date">Date and Time</span></h3>

    <center>

        <table class="tablesorter" style="width: 80%" border="1" >


            <thead>
            <tr>
                <th>Position</th>
                <th>Statistic</th>
                <th>Value</th>
            </tr>
            </thead>
            <tbody>

            <tr id="appUserStatTbl" >
                <td class="position"></td>

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+591.44505438

Maciej Bąk

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Aug 26, 2016, 8:15:53 AM8/26/16

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But heh, look at html ;]

<table id="appUserStatTbl" class="tablesorter" style="width: 80%" border="1" >
    <thead>
    <tr>
        <th>Position</th>
        <th>Statistic</th>
        <th>Value</th>
    </tr>
    </thead>
    <tbody>
    <tr>
        <td class="position"></td>

        <td>A</td>
        <td class="l-static-growth-rate"></td>
    </tr>


    <tr>
        <td class="position"></td>

        <td>B</td>
        <td class="l-mua"></td>
    </tr>


    <tr>
        <td class="position"></td>

        <td>C</td>
        <td class="l-wua"></td>
    </tr>

Diego Medina

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Aug 26, 2016, 12:03:56 PM8/26/16

to Lift

ok, now that I see your html, have a question, do you want the row with A to have a cell 1, row B to have cell 2, etc? so, can I just ignore the two rows after the first one? or do you need the group of 3 rows to repeat?

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Diego Medina

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Aug 26, 2016, 12:10:10 PM8/26/16

to Lift

scala> import xml.NodeSeq

import xml.NodeSeq

scala> import net.liftweb.util.Helpers._

import net.liftweb.util.Helpers._

scala>

scala> val x = <table id="appUserStatTbl" class="tablesorter" style="width: 80%" border="1" >

| <tbody>

| <tr>

| <td class="position"></td>

| <td>A</td>

| <td class="l-static-growth-rate"></td>

| </tr>

| </tbody>

| </table>

x: scala.xml.Elem =

<tbody>

<tr>

</tr>

</tbody>

</table>

scala>

scala> def css = "#appUserStatTbl ^^" #> "ignored" & "tr" #> 1.to(114).map { row => ".position *" #> row }

css: net.liftweb.util.CssSel

scala> css(x)

res4: scala.xml.NodeSeq =

NodeSeq(<table id="appUserStatTbl" class="tablesorter" style="width: 80%" border="1">

<tbody>

<tr>

</tr><tr>

</tr><tr>

</tr><tr>

</tr><tr>

</tr><tr>

<td class="l-static-g...

scala>

appUserStatTbl ^^ makes the next selector start just after it, ignoring if there are other tr anywhere on your page inside this snippet scope

Maciej Bąk

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Aug 29, 2016, 3:33:56 AM8/29/16

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Eh thanks for help :) But it just copies it 114 times..

Look in my example I have 114 diffenr positions, whhich I first render with proper values, then I want to numerate them..

W dniu piątek, 26 sierpnia 2016 08:46:00 UTC+2 użytkownik Maciej Bąk napisał:

Maciej Bąk

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Aug 29, 2016, 7:34:17 AM8/29/16

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Ah well, Ive changed solution completly finally.

Im putting tr values from scala code, this solution is ok to numerate everything well + its easier to test it later :)

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