Cast tree() into a subgraph()

[Olav Laudy]

Hi,

I have a graph that contains cyclic structures. In order to simplify the viewing of the structure, (in other software), I used to create a tree out of it and view the tree instead.

In Gremlin, I make use of subgraph() to display a small portion of my larger graph.

I can use tree() to create a tree structure, however, I don't see how I can make a subgraph after I created a tree.

This is my query so far:

g.V().has('name','W').as('source') \

                          .repeat(__.inE().as('in') \

                          .where('in',neq('source')).by(outV().id()).by(id()) \

                          .subgraph('subGraph').outV().as('out')) \

                          .times(3).cap('subGraph')

as you can see, I prevent nodes coming back to the first level ('source') by my where statement. If I want to generalize this, I'd have to keep track of all the nodes that I passed so far and use a 'within' statement for the lookup.

My question is how to collect the list of growing nodes over the repeat and use them in the within statement. 

Thanks!

Olav

[Daniel Kuppitz]

Aggregate everything (all edges) along the path and use the collection to filter previously seen edges.

g.V().has('name','W').

  repeat(inE().where(without('x')).aggregate('x').

         subgraph('s').outV()).

    times(3).

  cap('s')

Cheers,

Daniel

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