Gremlin - vertex and distance sorted by distance.

[dp]

Hi

I have Vertices as [{name:"John",location:Geoshape.point(10,20)},{name:"John",location:Geoshape.point(11,21)},{name:"John",location:Geoshape.point(12,22)}]

I would like to fetch vertices nearest to a Geoshape.point(9,9) with in 10km radius.

g.V().hasLabel('PersonInfo').has('location',geoWithin(Geoshape.circle(9,9,10))).match(__.as('loc'),__.as('loc').map{it.get().value('location').getPoint().distance(Geoshape.point(9,9).getPoint())}.as('dis'))

I am able to get the list as 

==>{loc=v[40984688], dis=108.91375866495252}

==>{loc=v[16480], dis=108.91375866495252}

==>{loc=v[4216], dis=108.91375866495252}

==>{loc=v[8248], dis=108.91375866495252}

But I am looking for sorting by distance. match with order().by()  not working. Any help please.

-Thanks in Advance.

dp

[Robert Dale]

Looking at your results, we can see that a map is the output of that  traversal. Since you want to order by 'dis', that key must be selected.

// using some mock data

g.inject([

['loc': 'v1', 'point': 7],

['loc': 'v1', 'point': 3],

['loc': 'v1', 'point': 5],

['loc': 'v1', 'point': 1]]).unfold().

match(__.as('a'),__.as('a').map{it.get().get('point')*2}.as('dis')).select('a','dis').

  order().by(select('dis'),incr)

==>[a:[loc:v1,point:1],dis:2]

==>[a:[loc:v1,point:3],dis:6]

==>[a:[loc:v1,point:5],dis:10]

==>[a:[loc:v1,point:7],dis:14]

Robert Dale

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