has('x', eq('y')) that always returns false

[Guy Ellis]

Is there a syntax for:

has('x', <predicate>('y'))

that always returns false.

I have a really weird use case where I want to use "has" but I always want it to return false against all the vertices at that point in the traversal.

e.g.

has('dummy', eq('dummy'))

works for me but is very hacky. I want something like:

has(true, eq(false))

which semantically conveys the nonsensical usage that it will always be false.

[Marko Rodriguez]

Hi,

Can you replace your has(), with not(identity())?

Marko.

http://markorodriguez.com

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[Guy Ellis]

I think that might work - thanks Marko!

[Guy Ellis]

Marko - I couldn't get that syntax to work. How would I use that off "g.V()" for example to not return any results? Thanks.

[Daniel Kuppitz]

g.V().not(identity())

But if you don't want to waste too much compute power:

g.V().limit(0)

Cheers,

Daniel

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