Common properties of unconnected nodes

[Udit Sharma]

Sample Graph

g=TinkerGraph.open().traversal()

g.addV().property('type','student').property('id','student1').property('age','20').property('course','A').property('class','X'). addV().property('type','student').property('id','student2').property('age','20').property('course','A').property('class','Y')

Find the properties which are common among the nodes having id as 'student1' and 'student2'.

Expected Output

[key:course,value:A]

[key:type, value:student]

[key:age, value:20]

[Robert Dale]

g.V().properties().unfold().group().by(key).by(value).unfold().project('k','v').by(keys).by(local(select(values).unfold().group().by().by(count()).order(local).by(values,decr).unfold().limit(1).select(keys)))

==>[k:course,v:A]

==>[k:id,v:student2]

==>[k:type,v:student]

==>[k:class,v:X]

==>[k:age,v:20]

Robert Dale

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[Udit Sharma]

Thanks Robert,

But, the expected output is different from the actual output. Let me rephrase the problem again. Given id of two nodes as 'student1' and 'student2', find the properties where both the key and value pair matches. So in this case, the traversal should not generate [k:id,v:student2] and [k:class,v:X] as class and id are different for student1 and student2. 

Also assume that graph may have more than two nodes.

On Thu, Jun 21, 2018 at 4:25 PM, Robert Dale <rob...@gmail.com> wrote:

g.V().properties().unfold().group().by(key).by(value).unfold().project('k','v').by(keys).by(local(select(values).unfold().group().by().by(count()).order(local).by(values,decr).unfold().limit(1).select(keys)))

==>[k:course,v:A]

==>[k:id,v:student2]

==>[k:type,v:student]

==>[k:class,v:X]

==>[k:age,v:20]

Robert Dale

On Thu, Jun 21, 2018 at 2:12 AM Udit Sharma <ushar...@gmail.com> wrote:

Sample Graph

g=TinkerGraph.open().traversal()

g.addV().property('type','student').property('id','student1').property('age','20').property('course','A').property('class','X'). addV().property('type','student').property('id','student2').property('age','20').property('course','A').property('class','Y')

Find the properties which are common among the nodes having id as 'student1' and 'student2'.

Expected Output

[key:course,value:A]

[key:type, value:student]

[key:age, value:20]

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Thanks and Regards

Udit Sharma

MTech CSE, IITR

[Robert Dale]

g.V().or(has('id','student1'), has('id','student2')).properties().

    group().by(key).by(value).unfold().

    project('k','v').by(keys).by(select(values).unfold().groupCount()).

    filter(select('v').select(values).unfold().is(gte(2))).

    select('k','v').by().by(select(keys).unfold())

==>[k:course,v:A]

==>[k:type,v:student]

==>[k:age,v:20]

Robert Dale

On Thu, Jun 21, 2018 at 7:17 AM Udit Sharma <ushar...@gmail.com> wrote:

Thanks Robert,

But, the expected output is different from the actual output. Let me rephrase the problem again. Given id of two nodes as 'student1' and 'student2', find the properties where both the key and value pair matches. So in this case, the traversal should not generate [k:id,v:student2] and [k:class,v:X] as class and id are different for student1 and student2. 

Also assume that graph may have more than two nodes.

On Thu, Jun 21, 2018 at 4:25 PM, Robert Dale <rob...@gmail.com> wrote:

g.V().properties().unfold().group().by(key).by(value).unfold().project('k','v').by(keys).by(local(select(values).unfold().group().by().by(count()).order(local).by(values,decr).unfold().limit(1).select(keys)))

==>[k:course,v:A]

==>[k:id,v:student2]

==>[k:type,v:student]

==>[k:class,v:X]

==>[k:age,v:20]

Robert Dale

On Thu, Jun 21, 2018 at 2:12 AM Udit Sharma <ushar...@gmail.com> wrote:

Sample Graph

g=TinkerGraph.open().traversal()

g.addV().property('type','student').property('id','student1').property('age','20').property('course','A').property('class','X'). addV().property('type','student').property('id','student2').property('age','20').property('course','A').property('class','Y')

Find the properties which are common among the nodes having id as 'student1' and 'student2'.

Expected Output

[key:course,value:A]

[key:type, value:student]

[key:age, value:20]

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Thanks and Regards

Udit Sharma

MTech CSE, IITR

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